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2 years ago

Graph the line y= 2/3x +1

Mathematics

2 answers:

lbvjy [14]2 years ago

8 0

$\huge\boxed{Hello,\:hope\:you\:are\:having\:a\:wonderful\:day.}$ We are asked to graph the line y=2/3x+1.

2/3 is the slope of this line (Rise/Run)

The rise is how many units we move up; the run is how many units we move left or right.

For this line, 2 is the rise, and 3 is the run.

Now, 1 is the y-intercept. (where the graph touches the y-axis)

First, plot this point: (0,1)

Then, move 2 units up and 3 to the left (Up 2, over 3, up 2, over 3)

When you have a line, take a ruler and connect these points, and you will have the graph of y=2/3x+1.

$\huge\bold{Hope\:it\:helps!}$

$\huge\mathfrak{LoveLastsAllEternity}$

$\huge\sf{Good\:luck}$

Dmitry [639]2 years ago

3 0

Step-by-step explanation:

Given the linear equation, y = ⅔x + 1, where the <u>slope</u>, m = ⅔, and the y-intercept, (0, 1) where<em> b</em> = 1.

<h3><u>Start at the y-intercept:</u></h3>

In order to graph the given linear equation, start by plotting the coordinates of the y-intercept, (0, 1). As we know, the <u>y-intercept</u> is the point on the graph where it crosses the y-axis. It coordinates are (0, <em>b</em>), for which the value of b represents the value of the y-intercept in slope-intercept form, y = mx + b.

<h3><u>Plot other points using the slope:</u></h3>

From the y-intercept, (0, 1), we must use the slope, m = ⅔ (<em>rise</em> 2, <em>run</em> 3) to plot the other points on the graph. Continue the process until you have sufficient amount of plotted points on the graph that you could connect a line with.

Attached is a screenshot of the graphed linear equestion, which demonstrates how I plotted the other points on the graph using the "rise/run" techniques" discussed in the previous section of this post.

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Emelina wrote the equation of a line in point-slope form as shown below.

Harman [31]

Answer: $y=3x+2$

Step-by-step explanation:

Given: Emelina wrote the equation of a line in point-slope form as shown below.

$(y+4)=3(x+2)$

To write the equation in intercept form, first we multiply 3 inside the bracket values in the right side , we get

$y+4=3x+6$

Now, subtract 4 from both sides , we get

$y=3x+2$

Hence, Emelina’s equation in slope-intercept form : $y=3x+2$

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4 years ago

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The value 5 is an upper bound for the zeros of the function shown below.

Mice21 [21]

Answer:

The given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18 will be true.

Step-by-step explanation:

Given

$f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18$

We know the rational zeros theorem such as:

if $x=c$ is a zero of the function $f(x)$ ,

then $f(c) = 0$ .

As the $f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18$ is a polynomial of degree $4$ , hence it can not have more than $4$ real zeros.

Let us put certain values in the function,

$f(5) = 448$ , $f(4) = 126$ , $f(3) = 0$ , $f(2) = -20$ ,

$f(1) = 0$ , $f(0) = 18$ , $f(-1) = 16$ , $f(-2) = 0$ , $f(-3) = 0$

From the above calculation results, we determined that $4$ zeros as

$x = -3, -2, 1,$ and $3$ .

Hence, we can check that

$f(x) = (x+3)(x+2)(x-1)(x-3)$

Observe that,

$for x > 3$ , $f(x)$ increases rapidly, so there will be no zeros for $x>3$ .

Therefore, the given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18 will be true.

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3 years ago

Jenson has a basket containing oranges, apples, and pears. He picks a piece of fruit from the basket 40 times, replacing the fru

katovenus [111]

Answer:In this question, we're trying to find how many apples Jenson picked from the basket.

Lets gather information that can help us.

Important information:

Picked a fruit from a basket 40 times

Probability of picking an apple is 0.3

With the information above, we can solve the question.

We know that he picked up a fruit 40 times, but we need to find how many apples he picked up during the 40 times.

The probability of picking an apple is 0.3, which is equivalent to 30%

This means that 30% of the 40 times he picked an apple.

We would multiply 40 by 0.3 to get our answer.

This means that Jenson picked 12 apples.

I hope this helped you out.

Good luck on your academics.

Have a fantastic day!

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Step-by-step explanation:

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4 years ago

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50 POINTS !!!!!!!!

Bingel [31]

Answer:

Step-by-step explanation:

i wont tell you the answer but if you use brainly all the time you will not learn how to do it so try hard get a pen or a pencil get paper and stay confident you got this! i belive in you

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3 years ago

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onsider the following hypothesis test: H 0: 50 H a: > 50 A sample of 50 is used and the population standard deviation is 6. U

kondaur [170]

Answer:

a) z(e) > z(c) 2.94 > 1.64 we are in the rejection zone for H₀ we can conclude sample mean is great than 50. We don´t know how big is the population .We can not conclude population mean is greater than 50

b) z(e) < z(c) 1.18 < 1.64 we are in the acceptance region for H₀ we can conclude H₀ should be true. we can conclude population mean is 50

c) 2.12 > 1.64 and we can conclude the same as in case a

Step-by-step explanation:

The problem is concerning test hypothesis on one tail (the right one)

The critical point z(c) ; α = 0.05 fom z table w get z(c) = 1.64 we need to compare values (between z(c) and z(e) )

The test hypothesis is:

a) H₀ ⇒ μ₀ = 50 a) Hₐ μ > 50 ; for value 52.5

b) Hₐ μ > 50 ; for value 51

c) Hₐ μ > 50 ; for value 51.8

With value 52.5

The test statistic z(e) ??

a) z(e) = ( μ - μ₀ ) /( σ/√50) z(e) = (2.5*√50 )/6 z(e) = 2.94

2.94 > 1.64 we are in the rejected zone for H₀ we can conclude sample mean is great than 50. We don´t know how big is the population .We can not conclude population mean is greater than 50

b) With value 51

z(e) = ( μ - μ₀ ) /( σ/√50) ⇒ z(e) = √50/6 ⇒ z(e) = 1.18

z(e) < z(c) we are in the acceptance region for H₀ we can conclude H₀ should be true. we can conclude population mean is 50

c) the value 51.8

z(e) = ( μ - μ₀ ) /( σ/√50) ⇒ z(e) = (1.8*√50)/ 6 ⇒ z(e) = 2.12

2.12 > 1.64 and we can conclude the same as in case a

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3 years ago