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bogdanovich [222]
3 years ago
7

Which direction does the graph of the equation shown below open? Y^2-4x+4y-4=0

Mathematics
2 answers:
zavuch27 [327]3 years ago
8 0
We have that
Y²<span>-4x+4y-4=0
</span>you can rewrite the equation as 
4x=y²+4y-4
x=(y²/4)+y-1
x=0.25*(y²+4y)-1
x=0.25*(y²+4y+4-4)-1
x=0.25*(y²+4y+4)-5
x=0.25*(y+2)²-5

the equation of the parabola is of the form
x=a(y-k)²+h
is a horizontal parabola
where
(h,k)-----> is the vertex-----> (-5,-2)
a=0.25
a> 0--------> open to the right

the answer is
the option <span>D. Right
</span>
see the attached figure

Taya2010 [7]3 years ago
3 0

The answer is D, right because you rewrite the equation to a x= equation. Just by doing that, you know the equation has to be left or right. When rewriting the equation, the slope is positive, therefore it is facing right

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