Which direction does the graph of the equation shown below open? Y^2-4x+4y-4=0
2 answers:
We have that
Y²<span>-4x+4y-4=0
</span>you can rewrite the equation as
4x=y²+4y-4
x=(y²/4)+y-1
x=0.25*(y²+4y)-1
x=0.25*(y²+4y+4-4)-1
x=0.25*(y²+4y+4)-5
x=0.25*(y+2)²-5
the equation of the parabola is of the form
x=a(y-k)²+h
is a horizontal parabola
where
(h,k)-----> is the vertex-----> (-5,-2)
a=0.25
a> 0--------> open to the right
the answer is
the option <span>D. Right
</span>
see the attached figure
Y²<span>-4x+4y-4=0
</span>you can rewrite the equation as
4x=y²+4y-4
x=(y²/4)+y-1
x=0.25*(y²+4y)-1
x=0.25*(y²+4y+4-4)-1
x=0.25*(y²+4y+4)-5
x=0.25*(y+2)²-5
the equation of the parabola is of the form
x=a(y-k)²+h
is a horizontal parabola
where
(h,k)-----> is the vertex-----> (-5,-2)
a=0.25
a> 0--------> open to the right
the answer is
the option <span>D. Right
</span>
see the attached figure
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