Answer:
1.10 × 10⁻¹² m
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
Speed of Light = Wavelength times Frequency
Explanation:
<u>Step 1: Define</u>
ν = 2.73 × 10²⁰ Hz
<u>Step 2: Find wavelength</u>
3.0 × 10⁸ m/s = λ(2.73 × 10²⁰ Hz)
λ = 1.0989 × 10⁻¹² m
<u>Step 3: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules.</em>
1.0989 × 10⁻¹² m ≈ 1.10 × 10⁻¹² m
Answer:
An acidic substance is any substance with a pH of less than 7, the smaller the number the more acidic it is. ... An acid is a substance that donates hydrogen ions. Because of this, when an acid is dissolved in water, the balance between hydrogen ions and hydroxide ions is shifted.
Explanation:
Explanation:
decrease since the photons have to travel through a cloudier substance
Answer:
The mole and atonmicity of both the gases are different, the number of atoms is not same.
Explanation:
The number of atoms in a molecule (compound) depends on mole number and atomicity.
↬ Mole of 100 g H₂ = 100g ÷ 2u = 50 mole
∴Number of atoms in 100 g H₂
= 2 x 50 x 6.022 × 10²³
= 6.022 x 10²⁴ atoms
↬ Mole of 100 g He = 100g ÷ 4u = 25 mole
∴ Number of atoms in 100 g He
= 1 × 25 × 6.022 × 10²³
= 150.55 × 10²³
= 1.5055 x 10²⁵ atoms
Thus, The mole and atonmicity of both the gases are different, the number of atoms is not same.
<u>-TheUnknownScientist</u><u> 72</u>
Potassium dichromate reacts with sulfuric acid to form chromic acid, H₂CrO₄ which is a very strong oxidizing agent. The secondary alcohol, (<em>R</em>)-2-butanol will be oxidized in the presence of chromic acid, but it can only be as oxidized as far as the ketone, which is the product shown, 2-butanone.
Sodium borohydride is a reducing agent that will reduce a ketone or aldehyde to an alcohol. When sodium borohydride reacts with 2-butanone, it reduces it to 2-butanol. However, the alcohol is no longer chiral as it was in the beginning since the sodium borohydride can add a hydride to either face of the carbonyl, which results in a racemic mixture of alcohols. This explains why the product has the same refractive index and boiling point as (<em /><em>R</em>)-2-butanol, however, the product formed would no longer be optically active.