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lara31 [8.8K]
1 year ago
10

which of the following is true about cations?a. They are negatively charged and move toward an anodeb. They are negatively charg

ed and move toward a cathodec. They are positively charged and move toward an anoded. They are positively charged and move toward an cathode.
Chemistry
1 answer:
cupoosta [38]1 year ago
8 0

ANSWER

They are positively charged and move toward an anode

Option C

EXPLANATION

In electrochemical reaction, cation are positively charged. Since they are positively charged, they move toward negatively charged anode

There are two types of reaction which are oxidation and reduction reaction. At oxidation, the positively charged cations move towards the negatively charged anode.

Recall, that like charges attract and unlike charges repel.

Therefore, the correct answer is option C

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194.5 g of BCl₃ is present in 1 × 10²⁴ molecules of BCl₃.

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In order to convert the given number of molecules of BCl₃ to grams, first we have to convert the molecules to moles.

It is known that 1 moles of any element has 6.022×10²³ molecules.

Then 1 molecule will have \frac{1}{6.022*10^{23} } moles.

So 1*10^{24} molecules = \frac{1*10^{24} }{6.022*10^{23} } =1.66 moles

Thus, 1.66 moles are included in BCl₃.

Then in order to convert it from moles to grams, we have to multiply it with the molecular mass of the compound.

As it is known as 1 mole contains molecular mass of the compound.

As the molecular mass of BCl₃ will be

Molecular mass of BCl_{3}= Mass of Boron + (3*Mass of chlorine)

Mass of boron is 10.811 g and the mass of chlorine is 35.453 g.

Molar mass of BCl₃ = 10.811+(3×35.453)=117.17 g.

grams of BCl_{3}=Molar mass of BCl_{3}*Number of moles

grams of BCl_{3}=117.17*1.66=194.5 g

So, 194.5 g of BCl₃ is present in 1 × 10²⁴ molecules of BCl₃.

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