Answer: The interquartile range is preferred when the data are skewed or have outliers. An advantage of the standard deviation is that it uses all the observations in its computation.
Step-by-step explanation:
The interquartile range are resistant to outliers and can be used for data having glaring outliers.
Outliers are values that are too far away from the central value.
Interquartile range is a better option than standard deviation when there are a few extreme values and the distribution is skwed.
Explanation:
Unclear question. But I inferred this to be clear rendering of your question;
1) It is considered a circle and a certain point. The expressions dot inside the circle, dot on circle, or dot outside the text describe the position of a dot relative to a circle. In figure 2 are drawn: a circle C of center O, points on the circle, points outside the circle and points inside the circle. a) Name the points inside the circle; b) Name the points that belong to the circle; c) Name the points outside the circle.
2) Consider any point P and a circle C of center O and radius r. Compare the distance OP with the radius of the circle if: a) The point is inside the circle; b) The point is on the circle; c) The point is outside the circle.
Answer: A. x ≤ -3
x/3 - x-1/2 ≥ 1 would make x ≤ -3
Answer:
276 4/7 ft
Step-by-step explanation:
Let r1 represent the radius of the inner circle. Then its circumference in feet is ...
C = 2πr
66 = 2π(r1)
If the radius of the outer circle is (r1 +44), then its circumference is ...
C = 2π(r1 +44) = 2π(r1) +2π(44)
C = 66 +88π
Then the difference in the circumferences is ...
(66 +88π) - (66) = 88π
Using the given value of π, the difference in circumferences is ...
(88 ft)(22/7) = 1936/7 ft = 276 4/7 ft
Answer:
C. -36 3/10
Step-by-step explanation:
4 2/5 = 22/5
22/5 = 4.4
4.4(-8.25)
-36.3 = -36 3/10
Have a great day :3
