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Katarina [22]
3 years ago
5

A sulfuric acid solution containing 571.6 g of H2SO4 per liter of solution has a density of 1.329 g/cm3. Calculate (a) the mass

percentage, (b) the mole fraction, (c) the molality, (d) the molarity of H2SO4 in this solution.
Chemistry
1 answer:
IgorLugansk [536]3 years ago
6 0

Answer:

a) 43%

b) 0.122

c) 7.70 molal

d) 5.83 M

Explanation:

Step 1: Data given

Mass of H2SO4 = 571.6 grams

Density of H2SO4 = 1.329 g/cm³ this means 1.329 grams per 1 mL or 1329 grams per 1L

<em>a) Calculate mass percentage</em>

Mass % = (571.6 grams / 1329 grams)* 100% = <u>43%</u>

<em>b) Calculate mole fraction</em>

Number of moles H2SO4 = Mass H2SO4 / Molar mass H2SO4

Moles H2SO4 = 571.6 grams / 98.08 g/mol

Moles H2SO4 = 5.83 moles

Moles H2O = (1329 -571.6)/18.02 = 42.03 moles

Total moles = 5.83 + 42.03 = 47.86 moles

Mole fraction H2SO4 = Moles of solute (H2SO4)/ Total moles

Mole fraction H2SO4 = 5.83 moles / 47.86 moles

Mol fraction h2SO4 = <u>0.122</u>

<em>c) Calculate the molality</em>

Mass of solvent = 1329 grams - 571.6 grams = 757.4 grams = 0.7574 kg

Molality of H2SO4 = number of moles H2SO4 / mass of solvent

Molality H2SO4 = 5.83 moles / 0.7574 kg

Molality H2SO4 = <u>7.70 molal</u>

<em>d) Calculate Molarity </em>

Molarity H2SO4 = Number of moles H2SO4 / volume

Molarity H2SO4 = 5.83 moles / 1L = <u>5.83 M</u>

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In one molecule of caffeine (C₈H₁₀N₄O₂) there are eight carbon atoms:

n(C₈H₁₀N₄O₂) : n(C) = 1 : 8.

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n(C₈H₁₀N₄O₂) : n(N) = 1 : 4.

n(C₈H₁₀N₄O₂) = 0.4 mol; amount of the coffeine molecules.

0.4 mol : n(N) = 1 : 4.

n(N) = 0.4 mol · 4.

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4) Answer is: there are 7 moles of oxygen in 3.5 mol of caffeine.

In one molecule of caffeine (C₈H₁₀N₄O₂) there are two oxygen atoms:

n(C₈H₁₀N₄O₂) : n(O) = 1 : 2.

n(C₈H₁₀N₄O₂) = 3.5 mol; amount of the coffeine molecules.

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