Actually when we burn metal salts, we cannot actually
really see distinct lines to appear because in reality, they are not really
visible to the human eye. There is only a certain range of wavelength of light that
our eyes can see.
To state in other way, some metal salts will give off light which has wavelengths that are outside of the visible region of the electromagnetic spectrum.<span> </span>
Explanation:
To show - from E=mc²=hv show that wavelength=h/mv
Proof -
Given that,
E = mc²
E = hν
By equating both the equations, we get
mc² = hν
Because real particles do not travel at the speed of light, De Broglie submitted velocity ( v ) for the speed of light ( c ).
mv² = hν
Through the equation λ , de Broglie substituted v/λ for ν and arrived at the final expression that relates wavelength and particle with speed.
mv² = hv/λ
⇒λ = hv/mv²
⇒λ = h/mv
Hence showed.
Answer:
C) ball rollinflown a hill
Explanation:
The question asks to identify the endothermic process in the list of options. By way of elimination, we have;
A) condensation of water on a wind shield of a car
Condensation is an exothermic process. That is, heat is given out as the gases change into the liquid state of matter.
B) formation of copper
This is an exothermic process. Capture of electrons by a cation is always exothermic.
C) ball rollinflown a hill
This is the correct option. Energy is absorbed by the ball as it moves on the hill
D) formation of ice from liquid water
Freezing is an example of exothermic reaction. Heat is given off to the surroundings.
E) oxide from copper and oxygen
Formation of metal oxides and most reactions involving oxygen are exothermic reactions,
We are given with the following pairs:
<span>carbon and oxygen
hydrogen and helium
gold and silver
and we are asked if there is a pair that will produce the same spectrum. The answer is
</span>No two elements produce the same spectrum.This is because a light spectrum is unique to each element.
Answer:
Explanation:
If a substance is a limiting reactants then the chemical reaction will not last a long time because the reactant has a set limit it will stop reacting with the second reactant. Hope this helped :)
