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MatroZZZ [7]
3 years ago
12

He then takes a powerful magnet and positions it below the table and the keys. He finds that he is able to drag the keys along t

he table by moving the magnet. This demonstrates that
Chemistry
1 answer:
Mamont248 [21]3 years ago
7 0

C. magnetic forces act at a distance

Explanation:

Since he was able to drag the keys along the table by moving the magnet, it shows that magnetic forces acts a distance.

Magnetism is a property exhibited by a wide range of materials.

Around a bar magnet, there are field forces in which the forces of the magnets are felt.

  • Magnetic forces are non- contact forces. They don't need to be together to exert their force.
  • This is why magnetic forces act at a distance.

learn more:

Electromagnet brainly.com/question/2191993

#learnwithBrainly

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3 years ago
Use the following half-reactions to construct a voltaic cell:
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<u>Answer:</u> The correct answer is 3Ag^+(aq.)+Cr(s)\rightarrow 3Ag(s)+Cr^{3+}(aq.);E^o_{cell}=+1.53V

<u>Explanation:</u>

We are given:

Cr^{3+}(aq.)+3e^-\rightarrow Cr(s);E^o=-0.73V\\\\Ag^+(aq.)+e^-\rightarrow Ag(s);E^o=+0.80V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, silver will always undergo reduction reaction will get reduced.

Chromium will undergo oxidation reaction and will get oxidized.

The half reactions for the above cell is:

Oxidation half reaction: Cr(s)\rightarrow Cr^{3+}+3e^-;E^o_{Cr^{3+}/Cr}=-0.73V

Reduction half reaction: Ag^{+}+e^-\rightarrow Ag(s);E^o_{Ag^{+}/Ag}=0.80V       ( × 3)

Net equation:  3Ag^+(aq.)+Cr(s)\rightarrow 3Ag(s)+Cr^{3+}(aq.)

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=0.80-(-0.73)=1.53V

Hence, the correct answer is 3Ag^+(aq.)+Cr(s)\rightarrow 3Ag(s)+Cr^{3+}(aq.);E^o_{cell}=+1.53V

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