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liraira [26]
2 years ago
14

Which chemical change is most likely to involve bubbling or an odor? A. temperature decrease B. color change C. gas production D

. precipitate formation
Chemistry
1 answer:
weqwewe [10]2 years ago
6 0

C is the right answer

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A 1.000 mL sample of acetone, a common solvent sometimes used as a paint remover, was placed in a small bottle whose mass was kn
ra1l [238]

Answer:

See explanation

Explanation:

Precision means the reputability of measurement and accuracy means how close a measurement is to the actual value. To get the measured mass of the acetone we need to substract the mass of the bottle from the measured mass of bottle and acetone.

The mass of the bottle is 38.0015g

⇒The mass of acetone in bottle 1= 0.7783g

⇒Mass of acetone in bottle 2= 0.7780g

⇒Mass of acetone in bottle3= 0.7786g

The measured value is near to each other. ⇒ the measurements are <u>precise</u>.

To check the <u>accuracy</u> we can compare the average value to the actual mass of the acetone.

Average of the acetone measurement is (0.7783+0.7780+0.7786)/3 = 0.7783g

The percentage of difference of the average measurement to the actual mass is = {(actual value-measured value)/actual value}x100%

={(0.7791-0.7783)/0.7791}x100%

=0.10%

So we can see the difference is very small ⇒ the measurement is accurate.

7 0
3 years ago
Calculate the pH of a solution prepared by dissolving 0.370 mol of formic acid (HCO2H) and 0.230 mol of sodium formate (NaCO2H)
Veronika [31]

The question is incomplete, here is the complete question:

Calculate the pH of a solution prepared by dissolving 0.370 mol of formic acid (HCO₂H) and 0.230 mol of sodium formate (NaCO₂H) in water sufficient to yield 1.00 L of solution. The Ka of formic acid is 1.77 × 10⁻⁴

a) 2.099

b) 10.463

c) 3.546

d) 2.307

e) 3.952

<u>Answer:</u> The pH of the solution is 3.546

<u>Explanation:</u>

We are given:

Moles of formic acid = 0.370 moles

Moles of sodium formate = 0.230 moles

Volume of solution = 1 L

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:  

pH=pK_a+\log(\frac{[salt]}{[acid]})

pH=pK_a+\log(\frac{[HCOONa]}{[HCOOH]})

pK_a = negative logarithm of acid dissociation constant of formic acid = 3.75

[HCOONa]=\frac{0.230}{1}  

[HCOOH]=\frac{0.370}{1}

pH = ?  

Putting values in above equation, we get:  

pH=3.75+\log(\frac{0.23/1}{0.37/1})\\\\pH=3.54

Hence, the pH of the solution is 3.546

5 0
3 years ago
Chlorine and bromine are elements in Group VII.
Goryan [66]

Explanation:

Bromine is a chemical element with the symbol Br and atomic number 35. It is the third-lightest halogen, and is a fuming red-brown liquid at room temperature that evaporates readily to form a similarly coloured vapour. Its properties are intermediate between those of chlorine and iodine. Isolated independently by two chemists, Carl Jacob Löwig (in 1825) and Antoine Jérôme Balard (in 1826), its name was derived from the Ancient Greek βρῶμος ("stench"), referring to its sharp and disagreeable smell.

Bromine, 35Br

7 0
3 years ago
What are the 3 primary consumers and what are the 3 secondary consumers
goldenfox [79]
Primary:
Grasshopper
Mouse
Grass

Secondary:
Hawk
Snake
Coyote 
8 0
3 years ago
How many formula units are in 4.52 moles of H3SO3?<br> Type your answer
lakkis [162]

Answer:

The answer is 98.07848. We assume you are converting between grams H2SO4 and mole. You can view more details on each measurement unit: This compound is also known as Sulfuric Acid. The SI base unit for amount of substance is the mole. 1 grams H2SO4 is equal to 0.010195916576195 mole.

<u>Quick conversion chart of moles H2SO3 to grams</u>

1 moles H2SO3 to grams = 82.07908 grams

2 moles H2SO3 to grams = 164.15816 grams

3 moles H2SO3 to grams = 246.23724 grams

4 moles H2SO3 to grams = 328.31632 grams

5 moles H2SO3 to grams = 410.3954 grams

6 moles H2SO3 to grams = 492.47448 grams

7 moles H2SO3 to grams = 574.55356 grams

8 moles H2SO3 to grams = 656.63264 grams

9 moles H2SO3 to grams = 738.71172 grams

10 moles H2SO3 to grams = 820.7908 grams

7 0
3 years ago
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