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Mekhanik [1.2K]
2 years ago
13

For travel purposes,a touring company places all 33 travelers into equal sized groups . how many groups are there and how many t

ravelers are in each group
PLEASE HELP MEEE
Mathematics
1 answer:
Katyanochek1 [597]2 years ago
5 0

There are 3 groups of 11 travellers each or 11 groups of 3 travellers each.

Since we have 33 travellers and we need to divide them into equal sized groups, we need to find the factors of 33.

<h3 /><h3>Factors of 33</h3>

So, 33 = 1 × 33 = 3 × 11

So, the two factors of 33 we require are 3 and 11.

<h3 /><h3>The groups of travellers</h3>

Since 11 × 3 = 3 × 11,

So, 3 × 11 implies that we can have 3 groups of 11 travellers each and,

11 × 3 implies that we can have 11 groups of 3 travellers each.

So, there are 3 groups of 11 travellers each or 11 groups of 3 travellers each.

Learn more about factors of a number here:

brainly.com/question/2058395

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2 and five fifths = 3


I hope that's help. Good night .

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Please show your work:
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b . 4/5

60 :15 minute : 4

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In a certain​ fraction, the denominator is less 7 than the numerator. If 3 is added to both the numerator and​ denominator, the
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Answer:

original fraction =12/5

Step-by-step explanation:

let x = numerator

therefore

   x+3/x-7+3 =15/8

    x+3/x-4 =15/8

      8(x+3)=15(x-4)

      8x+24=15x-60

       84=7x

        84/7=x

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7 0
3 years ago
Fill in the blank with a constant, so that the resulting quadratic expression is the square of a binomial. $\[x^2 + 22x + \under
saw5 [17]

Answer:

$\[x^2 + 22x + 121\]$

Step-by-step explanation:

Given

$\[x^2 + 22x + \underline{~~~~}.\]$

Required

Fill in the gap

Represent the blank with k

$\[x^2 + 22x + k\]$

Solving for k...

To do this, we start by getting the coefficient of x

Coefficient of x = 22

<em />

Divide the coefficient by 2

Result = 22/2

Result = 11

Take the square of this result, to give k

k= 11^2

k= 121

Substitute 121 for k

$\[x^2 + 22x + 121\]$

The expression can be factorized as follows;

x^2 + 11x + 11x + 121

x(x + 11)+11(x+11)

(x+11)(x+11)

(x+11)^2

<em>Hence, the quadratic expression is </em>$\[x^2 + 22x + 121\]$<em></em>

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