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Mekhanik [1.2K]
2 years ago
13

For travel purposes,a touring company places all 33 travelers into equal sized groups . how many groups are there and how many t

ravelers are in each group
PLEASE HELP MEEE
Mathematics
1 answer:
Katyanochek1 [597]2 years ago
5 0

There are 3 groups of 11 travellers each or 11 groups of 3 travellers each.

Since we have 33 travellers and we need to divide them into equal sized groups, we need to find the factors of 33.

<h3 /><h3>Factors of 33</h3>

So, 33 = 1 × 33 = 3 × 11

So, the two factors of 33 we require are 3 and 11.

<h3 /><h3>The groups of travellers</h3>

Since 11 × 3 = 3 × 11,

So, 3 × 11 implies that we can have 3 groups of 11 travellers each and,

11 × 3 implies that we can have 11 groups of 3 travellers each.

So, there are 3 groups of 11 travellers each or 11 groups of 3 travellers each.

Learn more about factors of a number here:

brainly.com/question/2058395

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A welder requires 18 hours to do a job. After the welder and an apprentice work on a job for 6 hours, the welder moves to anothe
Dafna1 [17]

Answer:

the apprentice can complete the job in 30 hours by working alone.

Step-by-step explanation:

Given:

Number of hours required to complete a job by welder = 18 hours

Number of hours welder work on job = 6 hours.

Number of hours required by apprentice to complete the job = 14 hours

We need to find Number of hours required to complete a job by apprentice alone.

Solution:

Let Number of hours required to complete a job by apprentice alone be 'a'.

Also let the job completed be = 1

Now we know that ;

Time required on job is equal to sum of Number of hours welder work on job and Number of hours required by apprentice to complete the job.

framing in equation form we get

Time required on job =  6+14 =20\ hrs

Now we can say that;

each has done a fraction of the work so we will add to two fraction as number of hours of work done by Total number of hours required to do the work to complete 1 job.

so we can frame the equation as;

\frac{6}{18}+\frac{20}{a}=1

By reducing the fraction we get;

\frac{1}{3}+\frac{20}{a}=1

Now we will make the denominator common to solve the fraction we get;

\frac{1\times a}{3\times a}+\frac{20\times3}{a\times3}=1\\\\\frac{a}{3a}+\frac{60}{3a}=1

Now denominators are same so we will solve the numerator we get;

\frac{a+60}{3a}=1

Multiplying both side by 3a we get;

\frac{a+60}{3a}\times3a=1\times 3a\\\\a+60=3a

Combining the like terms we get;

3a-a=60\\\\2a=60

Dividing both side by 2 we get;

\frac{2a}{2}=\frac{60}{2}\\\\a=30\ hrs

Hence the apprentice can complete the job in 30 hours by working alone.

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3 years ago
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Answer:

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Answer:

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4. now subtract these two fractions.

5. your answer should be -11/8

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