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viva [34]
3 years ago
12

Joe counts 250 peach trees on 25% of the land he owns. He determined that there are 10 trees for every 1,000 square feet of land

. About how many acres of land does Joe own?
Mathematics
2 answers:
yulyashka [42]3 years ago
5 0
2.3 acres is the answer.
den301095 [7]3 years ago
4 0

Number of trees on \frac{1}{4} of the land Joe owns = 250 trees

Total Number of trees on the whole land Joe owns = 250 \times 4

= 1000 trees

Area of land covered with 10 trees = 1000

Area of land covered with 1 tree = \frac{1000}{10}

= 100 square feet

Therefore, Total land covered with 1000 trees = 1000 \times 100

= 100,000 square feet

Since 1 acre = 43560 square feet

So, Total acres of land owned by Joe = \frac{100000}{43560}

= 2.29 acre

= 2.3 acre

So, Joe owns 2.3 acres of land.

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USPshnik [31]

Answer:

Q M \cong R M \Rightarrow definition of midpoint

\overline{P M} \cong \overline{P M} \Rightarrow Reflexive property of congruence

\Delta P Q M \cong \Delta P R M \Rightarrow SSS congruence postulate

\angle Q \cong \angle R \Rightarrow CPCTC theorem

Step-by-step explanation:

Step 1: Since, M is the midpoint of the line segment QR.  

\overline{Q M} \cong \overline{R M} \Rightarrow  definition of midpoint

Step 2: The reflexive property of congruence states that a line segment or an angle or a shape is always equal to itself.  

\overline{P M} \cong \overline{P M} \Rightarrow Reflexive property of congruence.

Step 3: The SSS congruence postulate states that if three sides of a triangle are equal to three sides of another triangle, then the two triangles are congruent.

\Delta P Q M \cong \Delta P R M \Rightarrow  SSS congruence postulate

Step 4: CPCTC theorem states if two triangles are congruent then the sides and angles are also congruent.

\angle Q \cong \angle R \Rightarrow CPCTC theorem.

3 0
3 years ago
Consider the parametric equations
MArishka [77]

Answer:(a)x^2+2y^2=2

(b)In the attached diagram

Step-by-step explanation:Step 1: Multiply both equations by t

xt=t(cost -sint)\\ty\sqrt{2} =t(cost +sint)

Step 1:  Multiply both equations by t

xt=t(cost -sint)\\ty\sqrt{2} =t(cost +sint)

Step 2:We square both equations

(xt)^2=t^2(cost -sint)^2\\(ty)^2(\sqrt{2})^2 =t^2(cost +sint)^2

Step 3: Adding the two equations

(xt)^2+(ty)^2(\sqrt{2})^2=t^2(cost -sint)^2+t^2(cost +sint)^2\\t^2(x^2+2y^2)=t^2((cost -sint)^2+(cost +sint)^2)\\x^2+2y^2=(cost -sint)^2+(cost +sint)^2\\(cost -sint)^2+(cost +sint)^2=2\\x^2+2y^2=2 hopes this helps

5 0
3 years ago
For the given decimal −0.009, find the two integers closest to it.
asambeis [7]

Answer:

The two integers closest to -0.009 are -1 and 0

Step-by-step explanation:

we have the number

-0.009

Convert to fraction number

-0.009=-\frac{9}{1,000}

In a number line

-\frac{1,000}{1,000} < -\frac{9}{1,000}

Remember that

-\frac{1,000}{1,000}=-1\\\frac{0}{1,000}=0

so

-1 < -\frac{9}{1,000}

therefore

The two integers closest to -0.009 are -1 and 0

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