Madison used a coordinate plane to map out an L-shaped
1 answer:
Answer:
The perimeter of the garden is 14 yard.
Step-by-step explanation:
Consider the figure:
Each unit on the grid represents yard.
From the figure we can find that:
The length of FA is 3.5 yard
The length of EF is 3.5 yard
The length of DX is 2 yard
The length of CD is 2 yard
The length of CB is 1.5 yard
The length of AB is 1.5 yard
To find the perimeter of the garden we need to add all the length as shown:
Perimeter = FA + EF + DX + CD + CB + AB
Perimeter = 3.5 + 3.5 + 2 + 2 + 1.5 +1.5
Perimeter = 14 yards
Hence, the perimeter of the garden is 14 yard.
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Answer:
(a) The probability that all the next three vehicles inspected pass the inspection is 0.343.
(b) The probability that at least 1 of the next three vehicles inspected fail is 0.657.
(c) The probability that exactly 1 of the next three vehicles passes is 0.189.
(d) The probability that at most 1 of the next three vehicles passes is 0.216.
(e) The probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.
Step-by-step explanation:
Let <em>X</em> = number of vehicles that pass the inspection.
The probability of the random variable <em>X</em> is <em>P (X) = 0.70</em>.
(a)
Compute the probability that all the next three vehicles inspected pass the inspection as follows:
P (All 3 vehicles pass) = [P (X)]³
Thus, the probability that all the next three vehicles inspected pass the inspection is 0.343.
(b)
Compute the probability that at least 1 of the next three vehicles inspected fail as follows:
P (At least 1 of 3 fails) = 1 - P (All 3 vehicles pass)
Thus, the probability that at least 1 of the next three vehicles inspected fail is 0.657.
(c)
Compute the probability that exactly 1 of the next three vehicles passes as follows:
P (Exactly one) = P (1st vehicle or 2nd vehicle or 3 vehicle)
= P (Only 1st vehicle passes) + P (Only 2nd vehicle passes)
+ P (Only 3rd vehicle passes)
Thus, the probability that exactly 1 of the next three vehicles passes is 0.189.
(d)
Compute the probability that at most 1 of the next three vehicles passes as follows:
P (At most 1 vehicle passes) = P (Exactly 1 vehicles passes)
+ P (0 vehicles passes)
Thus, the probability that at most 1 of the next three vehicles passes is 0.216.
(e)
Let <em>X</em> = all 3 vehicle passes and <em>Y</em> = at least 1 vehicle passes.
Compute the conditional probability that all 3 vehicle passes given that at least 1 vehicle passes as follows:
Thus, the probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.