Answer:
![x = \frac{4\sqrt{15}}{3}, x = \frac{-4\sqrt{15}}{3}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B4%5Csqrt%7B15%7D%7D%7B3%7D%2C%20x%20%3D%20%5Cfrac%7B-4%5Csqrt%7B15%7D%7D%7B3%7D)
or
![x = \frac{\pm4\sqrt{15}}{3}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B%5Cpm4%5Csqrt%7B15%7D%7D%7B3%7D)
Step-by-step explanation:
Hello!
Use the quadratic formula: ![x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B-b%20%5Cpm%20%5Csqrt%7Bb%5E2%20-%204ac%7D%7D%7B2a%7D)
First, let's convert our equation to standard form of a Quadratic: ax² + bx + c = 0
3x² = 80
3x² - 80 = 0
Note, thats the value of b will be 0, as there is no "bx"
Now, solve:
Plug in values
Simplify the radical (Discriminant)
Pull out perfect squares
Reduce factors
The solutions are ![x = \frac{4\sqrt{15}}{3}, x = \frac{-4\sqrt{15}}{3}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B4%5Csqrt%7B15%7D%7D%7B3%7D%2C%20x%20%3D%20%5Cfrac%7B-4%5Csqrt%7B15%7D%7D%7B3%7D)
There you go. Hope this helps.
The answer to fill the tank is 5.16
Answer:
The answer to your question is: g(3) = 34
Step-by-step explanation:
Function g(x) = 4(x)² - 3(x) + 7
g(3) = 4(3)² - 3(3) + 7 substitution
g(3) = 4(9) - 3(3) + 7 simplify
g(3) = 36 - 9 + 7
g(3) = 36 - 2
g(3) = 34
Answer:
válla si son brutos está bien fácil esa pregunta lo que pasa es que estoy haciendo mi trabajo