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forsale [732]
3 years ago
12

A 2 kg block slides down a 30 degrees incline as shown above with an acceleration of 2 m/s?

Physics
1 answer:
vovangra [49]3 years ago
4 0

The magnitude of the force acting up and down the incline is 16.97 N.

The given parameters:

  • <em>mass of the block, m = 2 kg</em>
  • <em>inclination of the plane, θ = 30⁰</em>
  • <em>speed of the block, v = 2 m/s</em>

<em />

The magnitude of the force acting up and down the incline is calculated as follows;

\Sigma F = 0 \\\\N - Wcos(\theta) = 0

where;

<em>N is the </em><em>normal reaction</em><em>, acting </em><em>upwards</em>

<em>W is the </em><em>weight </em><em>of the block, acting </em><em>downwards</em>

N = W cos (\theta)\\\\N = mg \ cos(\theta)\\\\N = 2 \times 9.8 \times cos(30)\\\\N = 16.97 \ N

Thus, the magnitude of the force acting up and down the incline is 16.97 N.

Learn more about forces on inclined plane: brainly.com/question/13881699

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