Question

A 2 kg block slides down a 30 degrees incline as shown above with an acceleration of 2 m/s?

Answer 1

The magnitude of the force acting up and down the incline is 16.97 N.

The given parameters:

• mass of the block, m = 2 kg
• inclination of the plane, θ = 30⁰
• speed of the block, v = 2 m/s

The magnitude of the force acting up and down the incline is calculated as follows;

$\Sigma F = 0 \\\\N - Wcos(\theta) = 0$

where;

N is the normal reaction, acting upwards

W is the weight of the block, acting downwards

$N = W cos (\theta)\\\\N = mg \ cos(\theta)\\\\N = 2 \times 9.8 \times cos(30)\\\\N = 16.97 \ N$

Thus, the magnitude of the force acting up and down the incline is 16.97 N.

Learn more about forces on inclined plane: brainly.com/question/13881699