Answer:
You will do twice the work of climbing 1 stair.
Explanation:
To obtain the answer to the question, we shall determine the work done on each case. This is illustrated below:
Case 1 ( climbing 2 stairs):
Mass (m) = m
One stair = 4 m
Height (h) = 2 × 4 = 8 m
Acceleration due to gravity (g) = 10 m/s²
Workdone 1 (Wd₁) =?
Wd₁ = mgh
Wd₁ = m × 10 × 8
Wd₁ = 80 × m
Case 2 (Climbing 1 stair)
Mass (m) = m
Height (h) = 4 m
Acceleration due to gravity (g) = 10 m/s²
Workdone 2 (Wd₂) =?
Wd₂ = mgh
Wd₂ = m × 10 × 4
Wd₂ = 40 × m
Now comparing the Workdone in both case:
Workdone 1 (Wd₁) = 80 × m
Workdone 2 (Wd₂) = 40 × m
Wd₁ / Wd₂ = 80 × m / 40 × m
Wd₁ / Wd₂ = 2
Cross multiply
Wd₁ = 2 × Wd₂
Thus, we can see that the Workdone in climbing 2 stairs is twice the Workdone in climbing 1 stair.
Therefore, you will do twice the work of climbing 1 stair.
<span>One half-life produces (1/2) of the decaying substance.
There would still be 48 atoms. But 24 would have thrown off
particles from their nucleuses, and only 24 would still be radioactive.</span>
The particle has constant acceleration according to
Its velocity at time 
is
Then the particle has position at time according to
At at the point (3, 6, 9), i.e. when 
, it has speed 8, so that
We know that at some time 
, the particle is at the point (5, 2, 7), which tells us
and in particular we see that
and
Then
That is, there are two possible initial velocities for which the particle can travel between (3, 6, 9) and (5, 2, 7) with the given acceleration vector and given that it starts with a speed of 8. Then there are two possible solutions for its position vector; one of them is
