The correct answer would be d (2,-5)
Answer:
a rectangle is twice as long as it is wide . if both its dimensions are increased 4 m , its area is increaed by 88 m squared make a sketch and find its original dimensions of the original rectangle
Step-by-step explanation:
Let l = the original length of the original rectangle
Let w = the original width of the original rectangle
From the description of the problem, we can construct the following two equations
l=2*w (Equation #1)
(l+4)*(w+4)=l*w+88 (Equation #2)
Substitute equation #1 into equation #2
(2w+4)*(w+4)=(2w*w)+88
2w^2+4w+8w+16=2w^2+88
collect like terms on the same side of the equation
2w^2+2w^2 +12w+16-88=0
4w^2+12w-72=0
Since 4 is afactor of each term, divide both sides of the equation by 4
w^2+3w-18=0
The quadratic equation can be factored into (w+6)*(w-3)=0
Therefore w=-6 or w=3
w=-6 can be rejected because the length of a rectangle can't be negative so
w=3 and from equation #1 l=2*w=2*3=6
I hope that this helps. The difficult part of the problem probably was to construct equation #1 and to factor the equation after performing all of the arithmetic operations.
Answer:
$200
Step-by-step explanation:
To find Jeff's net worth, we will deduct all his debts (liabilities) from his assets (his properties).
ASSETS
Savings Account - $6000
Investments - $15000
Guitar - $1000
TOTAL - $22000
LIABILITIES
Student loans - $17000
Credit Card Debt - $1200
Outstanding car payment - $3600
TOTAL - $21800
NET WORTH = Assets - Liabilities
NW = $22000 - $21800
NW = $200
His net worth is $200.
1.63636363
I hope this helps you
divide 4480 by 40
And for the 1760 ft multiply that twice
