The given question describes a right triangle with with one of the angles as 20 degrees and the side adjacent to the angle 20 degrees is of length 5,000 feet. We are looking for the length of the side opposite the angle 20 degrees.

Let the required length be x, then

$\tan{20^o}=\cfrac{opp}{hyp}=\cfrac{x}{5,000}\\ \\ \Rightarrow x=5,000\tan{20^o}=1,819.85$

Therefore, the height of the airplane above the tower is 1,819.85 feet.

8 0

3 years ago

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The picture shows a barn door:

Hitman42 [59]

Answer:

(D)9 divided by sin 60 degrees

Step-by-step explanation:

From the given figure, using trigonometry

$\frac{BC}{AB}=sin60^{{\circ}}$

Substituting the given values, we get

$\frac{9}{AB}=sin60^{{\circ}}$

$\frac{9}{sin60^{\circ}}=AB$

$AB=\frac{9{\times}2}{\sqrt{3}}$

$AB=\frac{18}{\sqrt{3}}$

$AB=10.4 feet$

Thus, The length of the support AB is 9 divided by sin 60 degrees.

5 0

3 years ago

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