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Elodia [21]
2 years ago
13

On a coordinate plane, two parabolas open up. The solid-line parabola, labeled f of x, goes through (negative 2, 4), has a verte

x at (0, 0), and goes through (2, 4). The dashed-line parabola, labeled g of x, goes through (negative 6, 10), has a vertex at (negative 4, 6), and goes through (negative 2, 10).
What is the equation of the translated function, g(x), if

f(x) = x2?


g(x) = (x – 4)2 + 6

g(x) = (x + 6)2 – 4

g(x) = (x – 6)2 – 4

g(x) = (x + 4)2 + 6
Mathematics
2 answers:
MatroZZZ [7]2 years ago
6 0

The answer is D  just took the test.

34kurt2 years ago
4 1

Answer:

y = (x+4)^{2}+6

Step-by-step explanation:

The parabola with vertex at point (h,k) is described by the following model:

y - k = C\cdot (x-h)^{2}

The equation which satisfies the conditions described above:

y - 6 = (x+4)^{2}

y = (x+4)^{2}+6

The two points are evaluated herein:

x = -6

y =(-6+4)^{2}+6

y = (-2)^{2}+6

y = 4 + 6

y = 10

x = -2

y = (-2+4)^{2}+6

y = 2^{2} + 6

y = 4 + 6

y = 10

The equation of the translated function is y = (x+4)^{2}+6.

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