Answer:
y=Ae^(1.25t)
Step-by-step explanation:
From the expression y=Ae^kt
After two days of the experiment, y = 49 million, t=2
After four days of the experiment, y= 600.25 million, t=4
A is the amount of bacteria present at time zero and t is the time after the experiment (in days)
At t=2 and y =49
49=Ae^2k…………….. (1)
At t=4 and y = 600.25
600.25=Ae^4k………… (2)
Divide equation (2) by equation (1)
600.25/49=(Ae^4k)/(Ae^2k )
12.25=e^2k
Take natural log of both sides
ln(12.25) =2k
2.505 =2k
k=1.25
The exponential equation that models this situation is y=Ae^(1.25t)
Geometric with a common ratio of 4/3
9*4/3 = 12
12*4/3= 16
16 *4/3 =21 1/3
Answer:
D.
Step-by-step explanation:
Both have a slope or "rate of change" of 1/2 because going from (0,5)-->(2,6) on the first one you go right 2 units and up 1 and slope is rise over run or y/x values in this case it would be 1/2 and on the bottom function you can see it goes from (0,-2)-->(4,0) and this goes right 4 units and up 2 units same principal applies you get 2/4 which is equal to 1/2 also it being negative or not doesn't change whether the two functions have the same rate of change.
46 meters in total i think
Answer:
Perimeter = 2l + 2w //l=length, w=width
l = 44 + w
Now substitute 44 + w in place of l in the above equation and you have
2(44 + w) + 2w = 288
=> 88 + 2w + 2w = 288
=> 88 + 4w = 288
=> 4w = 200
=> w = 50 and l = 44 + 50 = 94
2*94 + 2*50=288
Step-by-step explanation:
