The perimeter of a standard basketball court is 288 feet. The length is 44 feet longer than the width. What are the dimensions o f the court?
1 answer:
Answer:
Perimeter = 2l + 2w //l=length, w=width
l = 44 + w
Now substitute 44 + w in place of l in the above equation and you have
2(44 + w) + 2w = 288
=> 88 + 2w + 2w = 288
=> 88 + 4w = 288
=> 4w = 200
=> w = 50 and l = 44 + 50 = 94
2*94 + 2*50=288
Step-by-step explanation:
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