That's the diagram..
(12×3) + 3(0.67×7) = 50.07inches²
≈ 50inches²
hope this helps
make it the brainliest if it's correct....
Answer:
Step-by-step explanation:
A1. C = 104°, b = 16, c = 25
Law of Sines: B = arcsin[b·sinC/c} ≅ 38.4°
A = 180-C-B = 37.6°
Law of Sines: a = c·sinA/sinC ≅ 15.7
A2. B = 56°, b = 17, c = 14
Law of Sines: C = arcsin[c·sinB/b] ≅43.1°
A = 180-B-C = 80.9°
Law of Sines: a = b·sinA/sinB ≅ 20.2
B1. B = 116°, a = 11, c = 15
Law of Cosines: b = √(a² + c² - 2ac·cosB) = 22.2
A = arccos{(b²+c²-a²)/(2bc) ≅26.5°
C = 180-A-B = 37.5°
B2. a=18, b=29, c=30
Law of Cosines: A = arccos{(b²+c²-a²)/(2bc) ≅ 35.5°
Law of Cosines: B = arccos[(a²+c²-b²)/(2ac) = 69.2°
C = 180-A-B = 75.3°
Answer:
330 day passes, 367 tournament passes
Step-by-step explanation:
Answer:
38.105
Step-by-step explanation:
The area of this triangle = 0.5 * b * c * sin(A)
= 0.5 * 11 * 8 *sin(60) sin(60) =
= .866025...
= 0.5 * 11 * 8 * .866025
= 38.105
I think it is 2 I am trying to solve it only 4th grade