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bixtya [17]
2 years ago
11

Heres an easy question. Solve this.

}{5}" alt="\frac{1}{5}" align="absmiddle" class="latex-formula">y = 10
Mathematics
1 answer:
Grace [21]2 years ago
3 0

Answer:

y=50

Step-by-step explanation:

\frac{1}{5}y=10

 y=10÷\frac{1}{5}

   =50

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For every 12 students that wore sneakers, there were 9 students that wore boots. How many students wore sneakers if 24 students
Olenka [21]

Answer:

C (32)

Step-by-step explanation:

12 sneakers / 9 boots = x sneakers / 24 boots

the ratio is 4:3 so divide 24 by 3 and multiply by 4

12 / 9 = (24 / 3 x 4) / 24

12 / 9 = 32 / 24

32 students wore sneakers

7 0
3 years ago
Read 2 more answers
1/2(a+b)-(a-b)exponent2 when a=18 and b=14
lora16 [44]

Answer:

0

Step-by-step explanation:

Substitute the given values for a and b into the expression

\frac{1}{2}(18 + 14) - (18 - 14)²

= \frac{1}{2} × 32 - 4²

= 16 - 16

= 0

8 0
3 years ago
The total length of the stage is 76 feet. If the trap doors are centered across the stage, what is the distance from the left si
weqwewe [10]
 subtract the 26 1/2 from 76 and then divide by 2

76-26 1/2 = 49 1/2 / 2 = 24 3/4

5 0
3 years ago
A lacrosse player throws a ball into the air from a height of 6 feet with an initial vertical velocity of 64 feet per second. Wh
-Dominant- [34]

Answer:

Step-by-step explanation:

I'm going to use calculus to solve this, because it's the simplest way.  

The acceleration due to gravity in feet is the second derivative of the position function.  We will start with the acceleration and work backwards with antiderivatives to get to the position function.

a(t) = -32.  Going backwards and using the fact that the initial vertical velocity is 64 ft/sec, our velocity function is

v(t) = -32t + 64.  Going backwards and using the fact that the initial height of the ball is 6 feet, our position function is

s(t)=-16t^2+64t+6

The first part of this question asks us the maximum height of the ball.  From Physics, we learn that the maximum height of a projectile is reached when the velocity is 0, which happens to be right where the projectile stops for a nanosecond in the air to turn around and come back down.  We set the velocity function equal to 0 and solve for t.

0 = -32t + 64 and

0 = -32(t - 2).  By the Zero Product Property, either -32 = 0 or t - 2 = 0.  It's obvious that -32 does not equal 0, so t - 2 must equal 0.  Solving this for t:

t - 2 = 0 so

t = 2 seconds.  Since the maximum height is reached at a time of 2 seconds, we plug 2 seconds into the position function to get its position at 2 seconds (which is also the max height of the ball).

s(2)=-16(2)^2+64(2)+6 and

s(2) = -64 + 128 + 6 so

s(2) = 70 feet

Now we want to know when the ball will hit the ground.  "When" is a time value, and we know that the height of the ball on the ground is 0, so we sub in a 0 for s(t) and factor the quadratic.

Using the quadratic formula:

t=\frac{-64+/-\sqrt{4096-4(-16)(6)} }{-32} and

t=\frac{-64+/-\sqrt{4480} }{-32} which gives us the 2 solutions

t=\frac{-64+\sqrt{4480} }{-32} and

t=\frac{-64-\sqrt{4480} }{-32}

Plugging into your calculator, the first t = -.0916500 and the second t = 4.091

We all know that time cannot ever be negative, so our t value is 4.09.

Again, from Physics, we know that a projectile reaches it max height at halfway through its travels, so it just goes to follow logically that if it halfway through its travels at 2 seconds, then it will hit the ground at 4 seconds.  And it does!! How awesome is that?!

4 0
3 years ago
Vina has $4.70 in quarters, dimes and nickels in her purse. She has nine more dimes than quarters and four more nickels than qua
Aneli [31]

Step-by-step explanation:

Vina has $4.70 in quarters, dimes and nickels in her purse. She has nine more dimes than quarters and four more nickels than quarters. How many of each coin are in her purse?

nickels

dimes

quarters

4 0
2 years ago
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