<span>Consider a angle â BAC and the point D on its defector
Assume that DB is perpendicular to AB and DC is perpendicular to AC.
Lets prove DB and DC are congruent (that is point D is equidistant from sides of an angle â BAC
Proof
Consider triangles ΔADB and ΔADC
Both are right angle, â ABD= â ACD=90 degree
They have congruent acute angle â BAD and â CAD( since AD is angle bisector)
They share hypotenuse AD
therefore these right angle are congruent by two angle and sides and, therefore, their sides DB and DC are congruent too, as luing across congruent angles</span>
Answer: 48 inches tall
Step-by-step explanation: (I just learned this) First, you square 80 and 64. 80 will be 6400 and 64 will be 4096. Then you use the Pythagorean Theorem, which is a² + b² = c². A. and B. are the legs in a triangle and C. is the hypotenuse. If you have A. and C. but not B, you square A. and C. and subtract C. from A. Then, after you get the number, you square that number, which will be√(2304), which makes 48.
Answer:
Step-by-step explanation:
Answer:
option d is the correct answer.
Step-by-step explanation:
$80.00 x 0.20 = $16.00
$80.00 - 16.00 = $64.00
the hoodie costed $64.00
you were left with $16 to spare