Answer:
16384
Step-by-step explanation:
Answer:
(- 1, 1 )
Step-by-step explanation:
Given the 2 equations
2x - y = - 3 → (1)
x + y = 0 → (2)
Adding the 2 equations term by term will eliminate the term in y, that is
3x = - 3 ( divide both sides by 3 )
x = - 1
Substitute x = - 1 into either of the 2 equations and solve for y
Substituting into (2)
- 1 + y = 0 ( add 1 to both sides )
y = 1
Solution is (- 1, 1 )
Answer:
No one will be able to tell you without the picture. If it is face the same direction, it is a translation. If it is a mirror image, it is a reflection. 90 degree rotation means it was turned once. 180 degree rotation means it was turned twice and should be in the diagonal quadrant the pre-image started in.
Step-by-step explanation:
The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.