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NARA [144]
2 years ago
11

Why do we need to learn Positive and Negative Integers?

Mathematics
1 answer:
Masja [62]2 years ago
3 0

Tips for Success

Like any subject, succeeding in mathematics takes practice and patience. Some people find numbers easier to work with than others do. Here are a few tips for working with positive and negative integers:

Context can help you make sense of unfamiliar concepts. Try and think of a practical application like keeping score when you're practicing.

Using a number line showing both sides of zero is very helpful to help develop the understanding of working with positive and negative numbers/integers.

It's easier to keep track of the negative numbers if you enclose them in brackets.

Addition

Whether you're adding positives or negatives, this is the simplest calculation you can do with integers. In both cases, you're simply calculating the sum of the numbers. For example, if you're adding two positive integers, it looks like this:

5 + 4 = 9

If you're calculating the sum of two negative integers, it looks like this:

(–7) + (–2) = -9

To get the sum of a negative and a positive number, use the sign of the larger number and subtract. For example:

(–7) + 4 = –3

6 + (–9) = –3

(–3) + 7 = 4

5 + (–3) = 2

The sign will be that of the larger number. Remember that adding a negative number is the same as subtracting a positive one.

Subtraction

The rules for subtraction are similar to those for addition. If you've got two positive integers, you subtract the smaller number from the larger one. The result will always be a positive integer:

5 – 3 = 2

Likewise, if you were to subtract a positive integer from a negative one, the calculation becomes a matter of addition (with the addition of a negative value):

(–5) – 3 = –5 + (–3) = –8

If you're subtracting negatives from positives, the two negatives cancel out and it becomes addition:

5 – (–3) = 5 + 3 = 8

If you're subtracting a negative from another negative integer, use the sign of the larger number and subtract:

(–5) – (–3) = (–5) + 3 = –2

(–3) – (–5) = (–3) + 5 = 2

If you get confused, it often helps to write a positive number in an equation first and then the negative number. This can make it easier to see whether a sign change occurs.

Multiplication

Multiplying integers is fairly simple if you remember the following rule: If both integers are either positive or negative, the total will always be a positive number. For example:

3 x 2 = 6

(–2) x (–8) = 16

However, if you are multiplying a positive integer and a negative one, the result will always be a negative number:

(–3) x 4 = –12

3 x (–4) = –12

If you're multiplying a larger series of positive and negative numbers, you can add up how many are positive and how many are negative. The final sign will be the one in excess.

Division

As with multiplication, the rules for dividing integers follow the same positive/negative guide. Dividing two negatives or two positives yields a positive number:

12 / 3 = 4

(–12) / (–3) = 4

Dividing one negative integer and one positive integer results in a negative number:

(–12) / 3 = –4

12 / (–3) = –4

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Suppose the standard deviation of a normal population is known to be 3, and H0 asserts that the mean is equal to 12. A random sa
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Answer:

z=\frac{12.95-12}{\frac{3}{\sqrt{36}}}=1.9  

p_v =P(z>1.9)=0.0287  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=12.95 represent the sample mean

\sigma=3 represent the population standard deviation for the sample  

n=36 sample size  

\mu_o =12 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal to 12, the system of hypothesis would be:  

Null hypothesis:\mu \leq 12  

Alternative hypothesis:\mu > 12  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{12.95-12}{\frac{3}{\sqrt{36}}}=1.9  

P-value  

Since is a right tailed test the p value would be:  

p_v =P(z>1.9)=0.0287  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.  

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  • The information to complete the table is given below:
  • Equation that shows the relationship between the cost per night C and the number of people staying in the chalet n:                              C=  4000-100(n-1)

<h3>What is Equation?</h3>

An equation is a mathematical expression that contains an equals symbol. Equations often contain algebra. Algebra is used in math when you do not know the exact number in a calculation.

Given that:

Pules Rs 4000 per night but will decrease the amount by R100 per person occupying the chalet.

Number of People          Cost per night

          1                                       4000

          2                                       3900

          3                                      3800

          4                                       3700

          5                                       3600

          6                                       3500

          7                                       3400

          8                                       3300

          9                                       3200

          10                                      3100

let C be cost per night and n be the number of people of staying in chalet.

equation:   C=  4000-100(n-1)

      for n=1: C= 4000- 0=4000

            n=2, C= 4000-100(1)= 3900

The graph is attached below:

Learn more about equation here:

brainly.com/question/10413253

#SPJ1

     

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