Answer:
4) 120π cm^2
5) 56π cm^2
6) 32π cm^2
Step-by-step explanation:
Surface Area of Cylinder = 2π
+ (2πr)(height)
(will use variable h for height)
4)
diameter = 8 cm
r = 0.5(diameter) = 0.5(8) = 4 cm
height = 11 cm
2π
+ (2π)(4)(11)
= 2π(16) + 2π(44)
= 32π + 88π
= 120π cm^2
5)
diameter = 8 cm
r = 0.5(diameter) = 0.5(8) = 4 cm
height = 6 cm
2π + (2π)(4)(6)
= 2π(16) + 2π(12)
= 32π + 24π
= 56π cm^2
6)
diameter = 6 cm
r = 0.5(diameter) = 0.5(6) = 3 cm
height = 7 cm
2π
+ (2π)(3)(7)
= 2π(9) + 2π(7)
= 18π + 14π
= 32π cm^2
Answer:
1.66
Step-by-step explanation:
We need to conduct a chi square test
The statistic used to check this is given by the below
∑(n, 1) = [(O(i) - E(i)] / E(i)
From the question, we're told the observed value is
Freshmen
Sophomore
Junior
Senior.
After that, we then calculate the expected value.
Freshman
0.3 * 300 = $90
Sophomore
0.24 * 300 = $72
Statistics then finally gives us this
X² = (93 - 90²)/90 + (68 - 72)²/72 + (85 - 78)/78 + (64 -60)²/60
X² = 3² / 90 + 4² / 73 + 13² / 78 + 4² / 60
X² = 0.1 + 0.212 + 2.167 + 0.266 x+
X² = 2.745
X = √2.745
X = 1.66
Answer:
The value of x is -1.
Step-by-step explanation:
Simple equation:
☆Let's solve!
Add the whole numbers, including the decimals, then the variables like y and x.
Answer:
₹165.79
Step-by-step explanation:
Given:-
No. of electric bulbs = 1000
cost of each electric bulb = ₹ 150
No. of bulbs broken = 50
Selling price of each bulb = x
Profit percentage = 5%
To Find:-
The selling price of each bulb.
Solution:-
Cost price of 1000 electric bulbs,
= 1000 × ₹150
= ₹1,50,000
5% profit on the total cost price,
= {5}/{100}× ₹150000
= ₹7500
Total selling price = ₹157500
No. of bulbs remaining = 950
Therefore, selling price of each bulb,
= {₹157500}/{950}
= ₹165.79
Therefore,
Selling price of each bulb = ₹165.79
