This is one of those questions where, if you know the formula, it's easy,
and of you don't know the formula, there's no way.
In fact, the whole purpose of the question is to help you remember the formula.
The volume of a cylinder is
(pi) x (the radius)² x (the height).
For this particular cylinder, that's
(pi) x (3)² x (10) =
(pi) x (9) x (10) = 90 pi cubic units.
If you use (3.14) for (pi), then that's <em>282.6 cubic units</em>.
Answer:
The explanation of this question is given below in the explanation section
Step-by-step explanation:
The data is given in form of length and width.
Then, we need to convert it into improper fraction.
As you know that, the improper fraction is a fraction where the numerator (top number) is larger than the denominator (bottom number).
So, we converted it into improper fraction i.e.
Improper fraction= lenght/width
Then we reduce the fraction into lowest form and shown in ratio as depicted in attached picture with this solution.
Answer:55
Step-by-step explanation:
55
<h3>
Answer: 0.6</h3>
========================================
Work Shown:
sin(angle) = opposite/hypotenuse
sin(T) = VU/VT
sin(T) = 3/5
sin(T) = 0.6
Answer:
(2, 5)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y - 3x = 1
2y - x = 12
<u>Step 2: Rewrite Systems</u>
y - 3x = 1
- Add 3x on both sides: y = 3x + 1
<u>Step 3: Redefine Systems</u>
y = 3x + 1
2y - x = 12
<u>Step 4: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 2(3x + 1) - x = 12
- Distribute 2: 6x + 2 - x = 12
- Combine like terms: 5x + 2 = 12
- Isolate <em>x</em> term: 5x = 10
- Isolate <em>x</em>: x = 2
<u>Step 5: Solve for </u><em><u>y</u></em>
- Define equation: 2y - x = 12
- Substitute in <em>x</em>: 2y - 2 = 12
- Isolate <em>y </em>term: 2y = 10
- Isolate <em>y</em>: y = 5