Answer:
Correct option:
(B) <em>H₀</em>: <em>μ</em> = 2.40 vs. <em>Hₐ</em>: <em>μ</em> ≠ 2.40.
Step-by-step explanation:
The registrar of particular university in 1975 plans to look at records of students graduating last year to see if the mean GPA has changed from 2.40.
The registrar can use a single mean test to determine whether the mean has changed or not.
The hypothesis can be described as:
<em>H₀</em>: The mean GPA is 2.40, i.e. <em>μ</em> = 2.40.
<em>Hₐ</em>: The mean GPA is different from 2.40, i.e. <em>μ</em> ≠ 2.40.
To perform the test the registrar can either use a <em>z</em>-distribution or a <em>t</em>-distribution.
If the data provided gives some insight about the population standard deviation and the sample selected is quite large then the <em>z</em>-distribution can be used.
Otherwise it is wiser to use a <em>t</em>-distribution.
The decision rule is:
If the <em>p</em>-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.
Thus, the correct option is (B).
If AE is x+50, then the whole thing must be x=50.
if a portion of that, CE, is x+32, then the rest of it, AC, must be x+18.
Because no matter what X is, 32+18=50.
Answer:
C=25+5.50n
Step-by-step explanation:
C=25+5.50n where c is the total cost and n is the number of hours the clown entertains.
