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san4es73 [151]
2 years ago
8

A) Solve the equation: 4( − 5) = 8 + 8

Mathematics
1 answer:
Alex73 [517]2 years ago
5 0

Answer:

-20=16

Step-by-step explanation:

Given the following equation:

4(-5)=8+8

Due to the equation having no variable we do not have to solve for anything, but we can simplify.

4(-5)=8+8

4(-5)=4\times-5=-20

8+8=16

-20=16

Hope this helps.

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There are 2 different maps of California. The scale on the first map is 1cm to 20km. The distance from Fresno to San Francisco i
Oksi-84 [34.3K]

Answer:

75 km

Step-by-step explanation:

Given the following :

Scale on first map = 1cm to 20 km

Distance fromFresno to San Francisco = 15km on first map

Scale on 2nd map = 1cm to 100 km

1cm / 20km = 15km

Let of Distance from Fresno to San Francisco on 2nd map = d

1cm / 100km = d

1 : 20 = 15

1 : 100 = d

20/ 100 = 15/d

1/5 = 15/d

d = 15 * 5

d = 75 km

8 0
3 years ago
If arc AB =70 how many degrees are in ADB
storchak [24]
Somebody else had asked this question and they said it was 35 so your best bet is to go with 35
8 0
3 years ago
The radius of a cone is increasing at a constant rate of 7 meters per minute, and the volume is decreasing at a rate of 236 cubi
storchak [24]

Answer:

The rate of change of the height is 0.021 meters per minute

Step-by-step explanation:

From the formula

V = \frac{1}{3}\pi r^{2}h

Differentiate the equation with respect to time t, such that

\frac{d}{dt} (V) = \frac{d}{dt} (\frac{1}{3}\pi r^{2}h)

\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (r^{2}h)

To differentiate the product,

Let r² = u, so that

\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (uh)

Then, using product rule

\frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h\frac{du}{dt}]

Since u = r^{2}

Then, \frac{du}{dr} = 2r

Using the Chain's rule

\frac{du}{dt} = \frac{du}{dr} \times \frac{dr}{dt}

∴ \frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h(\frac{du}{dr} \times \frac{dr}{dt})]

Then,

\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]

Now,

From the question

\frac{dr}{dt} = 7 m/min

\frac{dV}{dt} = 236 m^{3}/min

At the instant when r = 99 m

and V = 180 m^{3}

We will determine the value of h, using

V = \frac{1}{3}\pi r^{2}h

180 = \frac{1}{3}\pi (99)^{2}h

180 \times 3 = 9801\pi h

h =\frac{540}{9801\pi }

h =\frac{20}{363\pi }

Now, Putting the parameters into the equation

\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]

236 = \frac{1}{3}\pi [(99)^{2} \frac{dh}{dt} + (\frac{20}{363\pi }) (2(99)) (7)]

236 \times 3 = \pi [9801 \frac{dh}{dt} + (\frac{20}{363\pi }) 1386]

708 = 9801\pi \frac{dh}{dt} + \frac{27720}{363}

708 = 30790.75 \frac{dh}{dt} + 76.36

708 - 76.36 = 30790.75\frac{dh}{dt}

631.64 = 30790.75\frac{dh}{dt}

\frac{dh}{dt}= \frac{631.64}{30790.75}

\frac{dh}{dt} = 0.021 m/min

Hence, the rate of change of the height is 0.021 meters per minute.

3 0
3 years ago
Can you please help me​
bulgar [2K]

Answer:

42

Step-by-step explanation:

G-14

O-14

O-14

so 14•3=42

8 0
2 years ago
Solve the system by substitution.<br> — 6x — 5y = 11<br> x = у
Margarita [4]

Answer:

(x, y) =(-1, - 1)

Step-by-step explanation:

-Substitute the value of x

-solve the equation

-Substitute the value of y

-check the possible solution

-check solution

-simplify

5 0
3 years ago
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