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Kryger [21]
4 years ago
14

Which triangle’s area would be calculated using the trigonometric area formula?

Mathematics
2 answers:
kati45 [8]4 years ago
7 0

Answer:

Triangle Q R P is shown. The length of Q R is 5 and the length of R P is 6. Angle Q R P is 40 degrees.

Step-by-step explanation:

The trigonometric formula refers the two sides length of the triangle and it also consists of included angle to find out the area

A = \frac{1}{2} ab sin C

QPR contains two sides and the included angle

XYZ has one side and the two angles

DEF has only three sides

And, the ABC contains two sides but does not have the included angle

Based on the explanation above, the correct option is B

BabaBlast [244]4 years ago
7 0

Answer: the second option aka B

Step-by-step explanation: The other person explained it and I'm just here to tell you they gave the correct and answer for edge 2020.

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G varies inversely with the square
vivado [14]

Answer:;4.4

Step-by-step explanation: Since it varies inversely we know G times H squared is equal to some constant, k. So we have G*H*H=k. We are told that when H=4, G=.25. Plugging this in, we have .25*4*4=k. This simplifies to 4=k. Our new equation is G*H*H=4. Now, we want to solve for G when H=.3. We plug it in. G*.3*.3=4 => G*.09=4. G=4/.09. This means G is approximately 44.4.

5 0
3 years ago
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A particle moves in a straight line so that its velocity at time
riadik2000 [5.3K]

Answer:

s(2) = 7.75

Step-by-step explanation:

given the velocity v(t) = t^3

we can find the position s(t) by simply integrating v(t) and using the boundary conditions s(1)=2

s(t) = \int {v(t)} \, dt\\ s(t) = \int {t^3} \, dt\\s(t) = \dfrac{t^4}{4}+c

we know throught s(1) = 2, that at t=1, s =2. we can use this to find the value of the constant c.  

s(1) = \dfrac{1^4}{4}+c\\4 = \dfrac{1^4}{4}+c\\c = 4-\dfrac{1}{4}\\c = \dfrac{15}{4} = 3.75

Now we can use this value of t to formulate the position function s(t):

s(t) = \dfrac{t^4}{4}+\dfrac{15}{4}\\

this is the position at time t.

to find the position at t=2

s(2) = \dfrac{2^4}{4}+\dfrac{15}{4}\\

s(2) = \dfrac{2^4}{4}+\dfrac{15}{4}\\

s(2) = \dfrac{31}{4} = 7.75

the position of the particle at time, t =2 is s(2) = 7.75

3 0
3 years ago
What’s a number that’s greater then or equal to 1 but less then 10?
statuscvo [17]
1-9 are all numbers that are less than 10, and 1 is included because the number can be greater than or equal to 1.

Hope this helped!
4 0
4 years ago
Read 2 more answers
Solve for a and b. please help.
Pachacha [2.7K]

Answer:

a= 22.5

b= 37.5

Step-by-step explanation:

<u>In</u><u> </u><u>△</u><u>BCD</u><u>:</u>

Applying Pythagoras' Theorem,

a² +30²= b²

a² +900= b² -----(1)

<u>In</u><u> </u><u>△</u><u>ABC</u><u>:</u>

Applying Pythagoras' Theorem,

b² +50²= (40 +a)² -----(2)

Substitute (1) into (2):

a² +900 +50²= 40² +2(40)(a) +a²<em> </em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>expand</em><em> </em><em>bracket</em><em>)</em>

a² +900 +2500= 1600 +80a +a²

a² +3400= a² +80a +1600 <em>(</em><em>simplify</em><em>)</em>

a² +3400 -a² -80a -1600= 0 <em>(</em><em>bring</em><em> </em><em>everything</em><em> </em><em>to</em><em> </em><em>1</em><em> </em><em>side</em><em>)</em>

-80a +1800= 0

80a= 1800 <em>(</em><em>+</em><em>8</em><em>0</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>

a= 1800 ÷80

a= 22.5

Subst. a= 22.5 into (1):

22.5² +900= b²

b²= 506.25 +900

b²= 1406.25

b= √1406.25 <em>(</em><em>square</em><em> </em><em>root</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>

b= 37.5 <em>(</em><em>reject</em><em> </em><em>negative</em><em> </em><em>value</em><em> </em><em>since</em><em> </em><em>b</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>length</em><em>)</em>

☆(a +b)²= a² +2ab +b²

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3 years ago
In order to solve the equation −3x + 6 = 5, the first step is to
Angelina_Jolie [31]
The first step is to subtract 6 from both sides to cancel it out. You will be left with -3x= -1.
6 0
3 years ago
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