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egoroff_w [7]
2 years ago
6

Please help me if you can​

Mathematics
1 answer:
Luda [366]2 years ago
5 0
A) 100 degrees (congruent angle)
B) 45 degrees (congruent angle)
C) 90 degrees (right angle)
D) 99 degrees (congruent angle)
E) 30 degrees (congruent angle)
F) 30 degrees (180-150=30, that is to find the other angle that is congruent to f)
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Factoring completely
Marianna [84]
This is called a difference of squares which always factors according to the rule for factoring the difference of squares....

(a^2+b^2)=(a+b)(a-b)  in this case:

9w^2-16 so

(3w-4)(3w+4)
4 0
3 years ago
I mark brainliest! please help!<br>which graph shows all the values that satisfy 2/9x+ 3&gt; 4 5/9​
disa [49]

Answer:

The first option

Step-by-step explanation:

2/9 x + 3 > 4 5/9

2/9x > 4 5/9 - 3

2/9x > 14/9

x > 14/9 ÷ 2/9

x > 7

6 0
3 years ago
Read 2 more answers
What is two less than 3 times a number is the same as the number plus 10.
d1i1m1o1n [39]
2 less than (3 times a number) is the same as (the number plus 10)
2 less than (3*x) = (x + 10)
3x - 2 = x + 10
From here, you solve! :)

3x - 2 - x = x + 10 - x
2x - 2 = 10
2x - 2 + 2 = 10 + 2
2x = 12
2x / 2 = 12 / 2
x = 6

Hope this helps! :)
6 0
4 years ago
50 POINTS !!!!!!!!
Bingel [31]

Answer:

Step-by-step explanation:

 i wont tell you the answer but if you use brainly all the time you will not learn how to do it so try hard get a pen or a pencil get paper and stay confident you got this! i belive in you

6 0
3 years ago
Read 2 more answers
A Confidence interval is desired for the true average stray-load loss mu (watts) for a certain type of induction motor when the
Vaselesa [24]

Answer:

A sample size of 35 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the width W as such

W = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

How large must the sample size be if the width of the 95% interval for mu is to be 1.0:

We need to find n for which W = 1.

We have that \sigma^{2} = 9, then \sigma = \sqrt{\sigma^{2}} = \sqrt{9} = 3. So

W = z*\frac{\sigma}{\sqrt{n}}

1 = 1.96*\frac{3}{\sqrt{n}}

\sqrt{n} = 1.96*3

(\sqrt{n})^2 = (1.96*3)^{2}

n = 34.57

Rounding up

A sample size of 35 is needed.

3 0
3 years ago
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