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4 years ago

Elizabeth works for Picasso paint supplies. Her annual salary is $72,580. What is Elizabeth’s annual social security deduction?

1 answer:

8 0

Social Security's Old-Age, Survivors, and Disability Insurance (OASDI) tax rate for wages paid in 2018 is set by the state at 6.2 % for employees and employers, each. An individual with wages equal to or larger than $128,400 would contribute $7,960.80 to the OASDI program. Since Elizabeth receives a salary of $72,580 from Picasso paint supplies, a lot lower than $128,400, there will be no deduction.

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sertanlavr [38]

Answer:

i think the answer will be 37 people own dogs

Step-by-step explanation:

some important information is that there are a total of 10,000 people in the town.
if you survey 120people
which 83 say yes to a dog
so you have to subtract the amount of people you surveyed which was 120 people - the 83 people who said yes.

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3 years ago

What is the degree? 6−n 2 +5n 3

Katyanochek1 [597]

Polynomial Degree:
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3 years ago

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dalvyx [7]

Answer:

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Step-by-step explanation:

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4 years ago

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Gnesinka [82]

Answer:

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Step-by-step explanation:

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3 years ago

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A cognitive psychologist wants to know whether memory performance is changed by old age. She randomly selects 7 elderly individu

defon

Answer:

$z = \frac{418.7-465.6}{\frac{53.6}{\sqrt{7}}}= -2.340$

Now we can calculate the p value with the following probability

$p_v =2*P(z$

If we use the commonly significance level of 0.05 we see that the p value is lower than these values we can conclude that the true mean is different from the value of 465.6 at 5% of significance

Step-by-step explanation:

Data provided

$\bar X=418.7$ represent the mean score on the standardized memory test

$\sigma=53.6$ represent the population standard deviation

$n=7$ sample size

$\mu_o =465.6$ represent the value that we want to verify

z would represent the statistic

$p_v$ represent the p value

System of hypothesis

We are interested to check if the memory performance for elderly individuals differs from that of the general population (mean different from 465.6), the system of hypothesis are then:

Null hypothesis: $\mu = 465.6$

Alternative hypothesis: $\mu \neq 465.6$

Since we know the population deviation we can use the z statistic from the z test for the true mean:

$z =\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$z = \frac{418.7-465.6}{\frac{53.6}{\sqrt{7}}}= -2.340$

Now we can calculate the p value with the following probability

$p_v =2*P(z$

If we use the commonly significance level of 0.05 we see that the p value is lower than these values we can conclude that the true mean is different from the value of 465.6 at 5% of significance

6 0

4 years ago