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Vsevolod [243]
3 years ago
5

Needs answered ASAP What is the volume of the triangular prism below?

Mathematics
1 answer:
neonofarm [45]3 years ago
5 0

Answer:

172.5 inches cubed

Step-by-step explanation:

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Please help! 20 points!
MakcuM [25]

12/3 = 4

 it was dilated with a scale factor of 4

6 0
3 years ago
15 POINTS!!!!
olganol [36]

p/5 + 6 = 10

=> p/5 = 10-6

=> p/5 = 4

=> p = 5×4

=> p = 20

C. 20

4 0
3 years ago
Read 2 more answers
What is the solution to the equation 3 square root x+4+3 square root 2x+8=0? x = –12 x = –4 x = 4 x = 12
Gre4nikov [31]

Answer:

x=-4

Step-by-step explanation:

3 0
3 years ago
(5) Find the Laplace transform of the following time functions: (a) f(t) = 20.5 + 10t + t 2 + δ(t), where δ(t) is the unit impul
Aloiza [94]

Answer

(a) F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}

(b) F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}

Step-by-step explanation:

(a) f(t) = 20.5 + 10t + t^2 + δ(t)

where δ(t) = unit impulse function

The Laplace transform of function f(t) is given as:

F(s) = \int\limits^a_0 f(s)e^{-st} \, dt

where a = ∞

=>  F(s) = \int\limits^a_0 {(20.5 + 10t + t^2 + d(t))e^{-st} \, dt

where d(t) = δ(t)

=> F(s) = \int\limits^a_0 {(20.5e^{-st} + 10te^{-st} + t^2e^{-st} + d(t)e^{-st}) \, dt

Integrating, we have:

=> F(s) = (20.5\frac{e^{-st}}{s} - 10\frac{(t + 1)e^{-st}}{s^2} - \frac{(st(st + 2) + 2)e^{-st}}{s^3}  )\left \{ {{a} \atop {0}} \right.

Inputting the boundary conditions t = a = ∞, t = 0:

F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}

(b) f(t) = e^{-t} + 4e^{-4t} + te^{-3t}

The Laplace transform of function f(t) is given as:

F(s) = \int\limits^a_0 (e^{-t} + 4e^{-4t} + te^{-3t} )e^{-st} \, dt

F(s) = \int\limits^a_0 (e^{-t}e^{-st} + 4e^{-4t}e^{-st} + te^{-3t}e^{-st} ) \, dt

F(s) = \int\limits^a_0 (e^{-t(1 + s)} + 4e^{-t(4 + s)} + te^{-t(3 + s)} ) \, dt

Integrating, we have:

F(s) = [\frac{-e^{-(s + 1)t}} {s + 1} - \frac{4e^{-(s + 4)}}{s + 4} - \frac{(3(s + 1)t + 1)e^{-3(s + 1)t})}{9(s + 1)^2}] \left \{ {{a} \atop {0}} \right.

Inputting the boundary condition, t = a = ∞, t = 0:

F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}

3 0
3 years ago
a. For a file whose size (in terms of number of bytes) is less than or equal to 12, then duplicate the contents of the file so t
pickupchik [31]

Answer:

#include <stdio.h>

int main()

{

int check;

char* dirname = "Subdir1";

check = mkdir(dirname,0766);

// check if directory is created or not

if (!check)

{

printf("Subdir1 Directory created\n");

 

char *dirname1="/Subdir1/D1";

if(mkdir("/Subdir1/D1", 0777)==-1)

{

printf("D1 Directory created\n");

int A1 = open ("/Subdir1/D1/A1.txt", 0666);

write(A1, "abcdefghij\n", strlen("abcdefghij\n"));

close(A1);

 

int A2 = open ("/Subdir1/D1/A2.txt", 0666);

write(A2, "you are beautiful\n", strlen("you are beautiful\n"));

close(A2);

 

int A3 = open ("/Subdir1/D1/A3.txt", 0666);

write(A3, "this is terrible!\n", strlen("this is terrible!\n"));

close(A3);

}

else

{

printf("Unable to create directory D1\n");

exit(1);

}

if(mkdir("/Subdir1/D2", 0777)==-1)

{

printf("D2 Directory created\n");

int B1 = open ("/Subdir1/D2/B1.ccc", 0664);

write(B1, "abcdefghij\n", strlen("abcdefghij\n"));

close(B1);

 

int B2 = open ("/Subdir1/D2/B2.ccc", 0664);

write(B2, "you are beautiful\n", strlen("you are beautiful\n"));

close(B2);

 

int B3 = open ("/Subdir1/D2/B3.ccc", 0664);

write(B3, "this is terrible!\n", strlen("this is terrible!\n"));

close(B3);

}

else

{

printf("Unable to create directory D2\n");

exit(1);

}

 

if(mkdir("/Subdir1/D3", 0777)==-1)

{

printf("D3 Directory created\n");

int C1 = open ("/Subdir1/D3/C1.txt", 0644);

write(C1, "abcdefghij\n", strlen("abcdefghij\n"));

close(C1);

 

int C2 = open ("/Subdir1/D3/C2.ddd", 0644);

write(C2, "you are beautiful\n", strlen("you are beautiful\n"));

close(C2);

 

int C3 = open ("/Subdir1/D3/C3.txt", 0644);

write(C3, "this is terrible!\n", strlen("this is terrible!\n"));

close(C3);

}

else

{

printf("Unable to create directory D2\n");

exit(1);

}

 

}

 

 

else {

printf("Unable to create directory Subdir1\n");

exit(1);

}

return 0;

}

Program 2:

#include <stdio.h>

 

long int findSize(char file_name[])

{

// opening the file in read mode

FILE* fp = fopen(file_name, "r");

 

// checking if the file exist or not

if (fp == NULL) {

printf("File Not Found!\n");

return -1;

}

 

fseek(fp, 0L, SEEK_END);

 

// calculating the size of the file

long int res = ftell(fp);

 

// closing the file

fclose(fp);

 

return res;

}

 

// Driver code

int main()

{

FILE *fptr1;

char c;

char file_name[] = {"D1.txt"};

long int res = findSize(file_name);

if (res != -1)

{

printf("Size of the file is %ld bytes \n", res);

if(res<=12)

{

fptr1 = fopen("D1.txt", "r");

c = fgetc(fptr1);

while (c != EOF)

{

fputc(c, fptr1);

c = fgetc(fptr1);

printf(c);

}

}

}

return 0;

}

4 0
3 years ago
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