For starters,
tan(2θ) = sin(2θ) / cos(2θ)
and we can expand the sine and cosine using the double angle formulas,
sin(2θ) = 2 sin(θ) cos(θ)
cos(2θ) = 1 - 2sin^2(θ)
To find sin(2θ), use the Pythagorean identity to compute cos(θ). With θ between 0 and π/2, we know cos(θ) > 0, so
cos^2(θ) + sin^2(θ) = 1
==> cos(θ) = √(1 - sin^2(θ)) = 4/5
We already know sin(θ), so we can plug everything in:
sin(2θ) = 2 * 3/5 * 4/5 = 24/25
cos(2θ) = 1 - 2 * (3/5)^2 = 7/25
==> tan(2θ) = (24/25) / (7/25) = 24/7
<span><u><em>The correct answer is:</em></u>
B.
<u><em>Explanation:</em></u>
In order to find the appropriate equation for this example, we need to <u>find one that works for the first point (1, 56). </u>
This means when we put 1 in for n in the equation, we need to get 56 as an answer.
If you place 1 in for n in each of the equations, only B gives you 56.
f(n) = 56(0.5)</span>ⁿ⁻¹<span>,
f(n) = 56(0.5)</span>⁰<span>,
f(n) = 56(1),
f(n) = 56. </span>
Answer:
ok! thank u
Step-by-step explanation:
Ans= 11-15
Explanation on next comment
