The volume of the frustum is volume of the whole cone(A) minus the smaller cone(B) which is would give the volume of frustum(C) = 256cm³
<h3>Calculation of a frustum</h3>
The volume of cone A V=πr²h/3
Where radius = 20cm
The volume of cone B = V=πr²h/3
Where radius = 12cm
Therefore volume of frustum =
V=π * 20² * h/3 - π * 12² *h/3
The variables will cancel out each other
V = 20² - 12²
V = 400- 144
V = 256cm³
Therefore, the volume of the frustum(C) = 256cm³
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Answer: 904.78 cu. ft
Step-by-step explanation:
Volume of sphere = 4/3 pi r^3
Assuming 12 ft. is the diameter of the sphere.
Answer:
it may be 115 if its a quadrilateral
The answer is <a is congruent to < d
because you already have <abe = <dbe
Answer:
the volume of the sphere is
Step-by-step explanation:
This problem bothers on the mensuration of solid shapes, sphere and cube.
Given data
Volume of cube v = 64 cubic inches
since we are dealing with a cube the height and the radius of the sphere is same as the sides of the cube,
we know that volume of cube is expressed as
![l= \sqrt[3]{64}](https://tex.z-dn.net/?f=l%3D%20%5Csqrt%5B3%5D%7B64%7D)
also diameter d=length l
Diameter d= 
Radius r = 
= 
= 
Height h=
we know that the volume of a sphere is given by
substituting into the formula we have
