Question

What is the difference of the polynomials? (â€""2x3y2 4x2y3 â€"" 3xy4) â€"" (6x4y â€"" 5x2y3 â€"" y5) â€""6x4y â€"" 2x3y2 9x2y3 â€"" 3xy4 y5 â€""6x4y â€"" 2x3y2 â€"" x2y3 â€"" 3xy4 â€"" y5 â€""6x4y 3x3y2 4x2y3 â€"" 3xy4 y5 â€""6x4y â€"" 7x3y2 4x2y3 â€"" 3xy4 â€"" y5.

Answer 1

Polynomial-An expression of two or more algebraic terms, which is the sum or difference of the several terms with having different power of the only variable. The difference between the given polynomials is

$=-2x^3y^2 + 9x^2y^3-3xy^4-6x^4y+y^5$

Given-

We have given two function of variable x and y

$(-2x^3y^2 + 4x^2y^3-3xy^4)$

$(6x^4y-5x^2y^3-y^5)$

Polynomial

An expression of two or more algebraic terms, which is the sum or difference of the several terms with having different power of the only variable.

Now we have to subtract the two equations to find the difference,

$(-2x^3y^2 + 4x^2y^3-3xy^4)-(6x^4y-5x^2y^3-y^5)$

Multiply the sign into the bracket to open the bracket and further solution,

$=-2x^3y^2 + 4x^2y^3-3xy^4-6x^4y+5x^2y^3+y^5$

Arrange the similar terms in the same groups,

$=-2x^3y^2 + (4x^2y^3+5x^2y)-3xy^4-6x^4y+y^5$$=-2x^3y^2 + 9x^2y^3-3xy^4-6x^4y+y^5$

Hence, the difference between the given polynomials is$=-2x^3y^2 + 9x^2y^3-3xy^4-6x^4y+y^5$

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