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elena55 [62]
3 years ago
5

Drawing length: 18 centimeters Actual Length: 450 meters​

Mathematics
1 answer:
bonufazy [111]3 years ago
4 0

Answer:

450 × 1 ÷ 12 = 37.5 mm

37.5 mm = 37.5 ÷ 10 = 3.75 cm

Step-by-step explanation:

dere yes indeed this that yes is..?

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What are the numbers
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4 years ago
Choose the expression that best represents the phrase below.
Arada [10]

20 more than the price of the meal is 20+p. Option-B is correct.

Given that,

The expression we have to get from 20 more than the price of the meal is.

Mathematical statements are called expressions if they have at least two terms that are related by an operator and contain either numbers, variables, or both. There are four types of mathematical operations: addition, subtraction, multiplication, and division.

Take the price of the meal as p.

20 more than the price of the meal is 20+p.

Therefore, 20 more than the price of the meal is 20+p. Option-B is correct.

To learn more about price visit: brainly.com/question/13731474

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1 year ago
Using the table find the value of y when x=2<br>​
Tju [1.3M]

Answer:

y = 8 when x = 2

Step-by-step explanation:

y = 4x

6 0
3 years ago
A common practice of airline companies is to sell more tickets for a particular flight than there are seats on the​ plane, becau
Serga [27]

Answer:

0.0159

Step-by-step explanation:

Given that a common practice of airline companies is to sell more tickets for a particular flight than there are seats on the​ plane, because customers who buy tickets do not always show up for the flight.

Here if X is the no of persons that do not show up, then X is binomial as each trial is independent with p = 0.04 and n =150 (no of tickets sold)

The plane is overbooked if more than 150 show up

i.e. less than 2 do not show up

Hence  the probability that the airline overbooked this​ flight

=P(X

4 0
3 years ago
Jacob solves the system of equations by forming a matrix equation.
Lyrx [107]

Simultaneous equations can be solved using inverse matrix operation.

The complete steps of Jacob's solution are:

\left[\begin{array}{cc}4&1\\-2&3\end{array}\right]^{-1} \cdot \left[\begin{array}{cc}4&1\\-2&3\end{array}\right]\left[\begin{array}{c}x&y\end{array}\right] = \frac{1}{14}\left[\begin{array}{cc}3&-1\\2&4\end{array}\right] \cdot \left[\begin{array}{c}2&-22\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{cc}4&1\\-2&3\end{array}\right] \cdot \left[\begin{array}{c}2&-22\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \frac{1}{14} \left[\begin{array}{c}28&-84\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{c}2&-6\end{array}\right]

We have:

4x + y = 2

-2x + 4y = -22

Calculate the determinant of \left[\begin{array}{cc}4&1\\-2&3\end{array}\right]

|A| = 4 \times 3 -1 \times -2

|A| = 12 +2

|A| = 14

So, the inverse matrix becomes

A = \frac{1}{14}\left[\begin{array}{cc}4&1\\-2&3\end{array}\right]

Replace the first column with \left[\begin{array}{c}2&-22\end{array}\right] to calculate the value of x

x = \frac{1}{14}\left[\begin{array}{cc}2&1\\-22&3\end{array}\right]

So, we have:

x = \frac{1}{14}(2 \times 3 - 1 \times -22)

x = \frac{1}{14}(6 +22)

x = \frac{1}{14}(28)

x = 2

Replace the second column with \left[\begin{array}{c}2&-22\end{array}\right] to calculate the value of y

y = \frac{1}{14}\left[\begin{array}{cc}4&2\\-2&-22\end{array}\right]

So, we have:

y = \frac{1}{14}(4 \times -22 - 2 \times -2)

y = \frac{1}{14}(-88 +4)

y = \frac{1}{14}(-84)

y = -6

Hence, the complete process is:

\left[\begin{array}{cc}4&1\\-2&3\end{array}\right]^{-1} \cdot \left[\begin{array}{cc}4&1\\-2&3\end{array}\right]\left[\begin{array}{c}x&y\end{array}\right] = \frac{1}{14}\left[\begin{array}{cc}3&-1\\2&4\end{array}\right] \cdot \left[\begin{array}{c}2&-22\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{cc}4&1\\-2&3\end{array}\right] \cdot \left[\begin{array}{c}2&-22\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \frac{1}{14} \left[\begin{array}{c}28&-84\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{c}2&-6\end{array}\right]

Read more about matrices at:

brainly.com/question/11367104

6 0
3 years ago
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