Answer:
y = 2x² - 10
Step-by-step explanation:
We must find a pattern in the numbers. Set out the numbers in a table (Columns 1 and 2 in the table).
<u>x</u> <u> y</u> <u>y/2</u> <u>y/2 + 5
</u>
2 -2 -1 4
3 8 4 9
4 22 11 16
5 40 20 25
It looks like all y-values are multiples of 2.
Let's divide them by 2 (Column 3).
The numbers don't increase evenly. We may have a quadratic function.
If we add 5 to each quotient, we get a set of values equal to x² (Column 4).
y/2 + 5 = x²
y + 10 = 2x²
y = 2x² - 10
The function is y = 2x² - 10.
Answer:
{f|0 ≤ f(x)}; x² - 4x + 5
Step-by-step explanation:
To find the Quadratic Equation, plug the <em>vertex</em> into the Vertex Equation FIRST, <em>y = </em><em>a</em><em>(</em><em>x</em><em> </em><em>-</em><em> </em><em>h</em><em>)</em><em>²</em><em> </em><em>+</em><em> </em><em>k</em>, where (<em>h</em><em>,</em><em> </em><em>k</em>) → (<em>2,</em><em> </em><em>1</em>)<em> </em>is the vertex, plus, -h gives you the OPPOSITE terms of what they really are, and k gives you the EXACT terms of what they really are: (x - 2)² + 1. Doing this will give you the Quadratic Equation of <em>x² - 4x + 5</em>. You understand now?
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2.3 + w > 18
-2.3 -2.3
w > 15.7
Answer:
6 years
Step-by-step explanation:
Here,
and we need to find 
.
So using the formula 
, we can find T by substituting the values
years
