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zloy xaker [14]
2 years ago
11

Help me out plesseee!!

Mathematics
1 answer:
nasty-shy [4]2 years ago
3 0

Step-by-step explanation:

the rate of change is officially

(f(x2) - f(x1)) / (x2 - x1)

but for a line function (as we have here) this is totally easy : it is the slope of the line.

and that means it is the factor of x.

in our case this is -3/2.

because the slope of a line is the ratio "y coordinate change / x coordinate change". and that is exactly corresponding to the general rate of change definition above.

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Adding/Subtracting rational expressions
Leona [35]
7]
 6/(x-1)-5x/4
subtracting the above we put the fraction under the same denominator:
 6/(x-1)-5x/4
multiplying the denominators we get:
4(x-1)
thus subtracting we get:
6/(x-1)-5x/4
=(4*6-5x(x-1))/[4(x-1)]
=[24-5x^2+5x]/(4x-4)
Answer:
(-5x^2+5x+24)/(4x-4)


9]
3/(x+7)+4/(x-8)
the common denominator is:
(x+7)*(x-8)=(x+7)(x-8)
thus adding the fractions we put them under the same denominator as follows:
[3(x-8)+4(x+7)]/[(x+7)(x-8)]
=[3x-24+4x+28]/[(x+7)(x-8)]
=(7x+4)/[(x+7)(x-8)]

5 0
3 years ago
There are 32 peanuts in a bag. Elliott takes 25% of peanut from the bag. Then Zaire fakes 50% of the remaining peanuts. How many
Novosadov [1.4K]

the answer is 12 peanuts!!





hope this helps

xx

3 0
3 years ago
Read 2 more answers
Find f'(x) and state the domain of f':<br> f(x) = In (2x^2+1)
-Dominant- [34]

Answer:

f'(x) = \frac{4x}{2x^2+1}

Domain: All Real Numbers

General Formulas and Concepts:

<u>Algebra I</u>

  • Domain is the set of x-values that can be inputted into function f(x)

<u>Calculus</u>

The derivative of a constant is equal to 0

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Chain Rule: \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Derivative: \frac{d}{dx} [ln(u)] = \frac{u'}{u}

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = ln(2x² + 1)

<u>Step 2: Differentiate</u>

  1. Derivative ln(u) [Chain Rule/Basic Power]:                          f'(x) = \frac{1}{2x^2+1} \cdot 2 \cdot 2x^{2-1}
  2. Simplify:                                                                                       f'(x) = \frac{1}{2x^2+1} \cdot 4x
  3. Multiply:                                                                                                     f'(x) = \frac{4x}{2x^2+1}

<u>Step 3: Domain</u>

We know that we would have issues in the denominator when we have a rational expression. However, we can see that the denominator would never equal 0.

Therefore, our domain would be all real numbers.

We can also graph the differential function to analyze the domain.

5 0
3 years ago
Please answer correctly!
VikaD [51]

Answer:

C ≈-1 and x≈8.1

Step-by-step explanation:


-sqrt(x + 2) - 3 = 4 - 2 abs(x - 3)

Using graphing technology, (see the graph)  they intersect at x≈-1 and x≈8.1

3 0
3 years ago
Read 2 more answers
The thumb length of fully grown females of a certain type of frog is normally distributed with a mean of 8.59 mm and a standard
PilotLPTM [1.2K]

Answer:

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 8.59, \sigma = 0.63

Calculate the probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

This is 1 subtracted by the pvalue of Z when X = 9.08. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{9.08 - 8.59}{0.63}

Z = 0.78

Z = 0.78 has a pvalue of 0.7823

1 - 0.7823 = 0.2177

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

8 0
3 years ago
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