Answer:
368 sq. units.
Step-by-step explanation:
We have a square of side lengths 20 units and we cut four congruent isosceles right triangles from the corners of the square.
Now, the four isosceles right triangles have one leg equal to 4 units.
Therefore, the area of four triangles =
sq. units.
Now, we have the area of the given square is (20 × 20) = 400 sq. units.
Therefore, the area of the remaining octagon will be (400 - 32) = 368 sq. units. (Answer)
![\frac{42}{j} = \frac{35}{55}](https://tex.z-dn.net/?f=%20%5Cfrac%7B42%7D%7Bj%7D%20%20%3D%20%20%5Cfrac%7B35%7D%7B55%7D%20)
to solve for j first you need to cross multiply;
j × 35 = 42 × 55
35j = 2,310
j = 2,310 ÷ 35 (did the inverse operation)
j = 66
Hope that helps :D
Using the cross product property on this proportion gives us the following equation:
20 (2x - 9) = 10 (9)
Use the distributive property and multiply
40x - 180 = 90
Add 180 to both sides
40x = 270
Divide 40 from both sides
x = 270/40
Simplify fraction
x = 27/4
This should be your answer. Let me know if you need any clarifications, thanks!
Answer:
k = 7
Step-by-step explanation:
Applying,
S = (y₂-y₁)/(x₂-x₁)................ Equation 1
Where S = slope of the line.
From the question,
Given: y₂ = 10, y₁ = 4, x₂ = k, x₁ = 1, S = 1
Substitute these values into equation 1
1 = (10-4)/(k-1)
crossmultiplying,
(k-1) = (10-4)
k-1 = 6
k = 6+1
k = 7