Answer:
there are 25 kg objective travelling at 2m/s to the right.
This group is called “noble gases” because they do not react with other elements. This is because they have a full valence shell.
You will use the Pythagorean Theorem to solve it.
c^2 = a^2 + b^2
c^2 = (1.5)^2 + (2)^2
c^2 = 6.25
c = square root of 6.25
c = 2.5
I hope this helps!
Answer:
tex]2.898\times 10^{-7}\ \text{m}[/tex] ultraviolet region
x-ray region
Explanation:
T = Temperature
b = Constant of proportionality = 
= Wavelength
From Wein's law we have
The wavelength of the radiation will be 
and it is in the ultraviolet region.
The wavelength of the radiation will be and it is in the x-ray region.
Answer:
See below
Explanation:
Normal force = m g cos 53 = 8 kg * 9.8 m/s^2 * cos 53 = 47.1823 N
no work is done by this force
Force friction = coeff friction * force normal = .4 * 47.1823 = 7.55 N
work of friction = 7.55 * 2 m = 15.1 j
Force Downplane = mg sin 53 = 62.61 N
work = 62.61 * 2 = 125.22 j
Net Force downplane = force downplane - force friction = 55.06 N
net Work = force * distance = 55.06 N * 2 M = 110.12 j
