Answer:
If the thrust is increased, the aircraft accelerates and the velocity increases. This is the second part sited in Newton's first law; a net external force changes the velocity of the object. The drag of the aircraft depends on the square of the velocity. So the drag increases with increased velocity.
Answer:
x = 1.018 m
Explanation:
given,
height of man = 190 cm
= 1.9 m
scale reading on left = 450 N
scale reading on the right = 390 N
Let center of gravity of man be x distance from feet, feet is on right side.
For system to be in equilibrium moment about center should be equal to zero.
∑M = 0
now,
450(1.9 - x ) - 390 × x = 0
450(1.9 - x ) = 390 × x
855 - 450 x = 390 x
840 x = 855
x = 1.018 m
hence, point of center of gravity from feet is equal to x = 1.018 m
Answer:
intensity of the light that emerges from the three filters is 560.80 W/m²
Explanation:
Given data
intensity I = 1375 W/m2
angle 1 = 31.0°
angle 2 = 41.0°
to find out
intensity of the light that emerges from the three filters
solution
we know intensity of light pass 1st polarize = I/2 = 1375 / 2 = 687.5 W/m2
so intensity after 2nd polarize pass = I 1st cos²(θ)
I 2nd = 687.5 cos²(31) = 687.5 ( 0.836754) = 575.27 W/m2
and
intensity after 3rd polarize pass = I 2nd cos²(θ)
I 3rd = 575.27 cos²(41) = 575.27 (0.974839) = 560.80 W/m2
so that intensity of the light that emerges from the three filters is 560.80 W/m²
