That it will erupt upon contact. Hope it helps!
Answer:
The acceleration of the car is 5m/s²
Explanation:
Given data
Force F= 4,000N
Mass of car m= 800kg
Acceleration a= ?
Applying the Newton's second law of motion which states that the rate of change of momentum of a body is proportional to the external force and takes place in the direction of the force
F=ma
a= F/m
a= 4000/800
a=5m/s²
Its b i belive
because it the only thing i saw on the list that conduts
Answer:
0.13 m/s
Explanation:
= Mass of first car = 140000 kg
= Mass of second car = 95000 kg
= Initial Velocity of first car = 0.3 m/s
= Initial Velocity of second car = -0.12 m/s
= Velocity of combined mass
For elastic collision
Their final velocity is 0.13 m/s
Answer:
Amplitude = 0.02m
Frequency = 640 Hz
Wavelength, λ = 0.5m
v = 320 m/s
Explanation:
Given the wave equation :
y=0.02 sin2π/0.5 (320t - x) where x and y are in
meters and t is in second
Comparing the above relation with the general wave equation :
y(x, t) = Asin2π/λ(wt - kx)
The amplitude, A = 0.02
From the equation :
2π/0.5 = 2π/λ
λ = 0.5 m
320t = vt
Hence, v = 320 m/s
Recall :
v = fλ
320 = f * 0.5
f = 320 / 0.5
f = 640 Hz
