2 years ago

If (5x-3y)²=0, then x/y=?

Mathematics

2 answers:

zhuklara [117]2 years ago

7 0

$(5x-3y)^2=0\\5x-3y=0\\5x=3y\\\dfrac{5x}{3y}=1\\\boxed{\dfrac{x}{y}=\dfrac{3}{5}}$

alexandr1967 [171]2 years ago

5 0

Answer:

$\frac{3}{5}$

Step-by-step explanation:

Given

(5x - 3y)² = 0, then

5x - 3y = 0 ( add 3y to both sides )

5x = 3y (divide both sides by 5 )

x = $\frac{3}{5}$ y ( divide both sides by y )

$\frac{x}{y}$ = $\frac{3}{5}$

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2 years ago

Graph 14x+34y=1 pretty please with a cherry on top!Also thank-you

Svetlanka [38]

To make it much easier, it should be converted to the slope-intercept form
y = mx + b

To do so, 14x + 34y = 1 turns to:
34y = -14x + 1

Divide both sides by 34:
$\frac{34y}{34} = \frac{-14}{34} x + \frac{1}{34}$
Simplified:
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Answer: $y = -\frac{7}{17} x + \frac{1}{34}$
Here is the graph: