3 years ago

If (5x-3y)²=0, then x/y=?

Mathematics

2 answers:

zhuklara [117]3 years ago

7 0

$(5x-3y)^2=0\\5x-3y=0\\5x=3y\\\dfrac{5x}{3y}=1\\\boxed{\dfrac{x}{y}=\dfrac{3}{5}}$

alexandr1967 [171]3 years ago

5 0

Answer:

$\frac{3}{5}$

Step-by-step explanation:

Given

(5x - 3y)² = 0, then

5x - 3y = 0 ( add 3y to both sides )

5x = 3y (divide both sides by 5 )

x = $\frac{3}{5}$ y ( divide both sides by y )

$\frac{x}{y}$ = $\frac{3}{5}$

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If (5x-3y)²=0, then x/y=?​

If (5x-3y)²=0, then x/y=?