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cestrela7 [59]
3 years ago
9

Yunika downloaded two applications for $2.99 each to her cell phone. The remaining applications that Yunika purchased cost $1.99

each.
If she downloaded x total applications, which of the following equations can be used to find how much Yunika spent on cell phone application downloads?
Mathematics
2 answers:
tatiyna3 years ago
8 0

Answer:

\text{How much Yunika spent} = 2(2.99\$) + (x-2)(1.99\$)

Step-by-step explanation:

First we know that Yunika spend 2.99$ in two applications then you have to  multiply by two.

Now if we know that the total of applications is represented as x and we already buy to of them then only remain x - 2 applications and each one of them cost 1.99$, then for get the total of  amount spent in this applications you have to multiply the applications by it's price per unit.

Finally for get how much Yunika spent you have two sum both expressions and get the result:

\text{How much Yunika spent} = 2(2.99\$) + (x-2)(1.99\$)

lorasvet [3.4K]3 years ago
3 0

Answer:

How is someone gonna answer the question if the equations arent even her to answer the question?

Step-by-step explanation:

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Elena L [17]
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3/2 x - 6  =  1/4 x + 4

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3 0
3 years ago
Which number is a solution of the inequality c &gt; 5?<br><br> A) 2<br> B) 2.5<br> C) 5<br> D) 6.5
Reil [10]

Answer:

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Step-by-step explanation:

4 0
3 years ago
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30 ⅓ % of 3 plz help me
Vikki [24]

Answer:

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Step-by-step explanation:

hope this answer will help you

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5 0
3 years ago
Type the correct answer in each box. If necessary, use / for the fraction bar(s).
Tom [10]

Given:

The values are a=0.\overline{6},b=0.75.

To find:

The values of ab and \dfrac{a}{b}.

Solution:

We have,

a=0.\overline{6}

a=0.666...                     ...(i)

Multiply both sides by 10.

10a=6.666...                 ...(ii)

Subtracting (i) from (ii), we get

10a-a=6.666...-0.666...

9a=6

a=\dfrac{6}{9}

a=\dfrac{2}{3}

And,

b=0.75

b=\dfrac{75}{100}

b=\dfrac{3}{4}

Now, the product of a and b is:

ab=\dfrac{2}{3}\times \dfrac{3}{4}

ab=\dfrac{1}{2}

The quotient of a and b is:

\dfrac{a}{b}=\dfrac{\dfrac{2}{3}}{\dfrac{3}{4}}

\dfrac{a}{b}=\dfrac{2}{3}\times \dfrac{4}{3}

\dfrac{a}{b}=\dfrac{8}{9}

Therefore, the required values are ab=\dfrac{1}{2} and \dfrac{a}{b}=\dfrac{8}{9}.

6 0
3 years ago
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