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olga_2 [115]
3 years ago
5

Find the slope of the line passing through the points (-1,8) and (-9,3).

Mathematics
2 answers:
vampirchik [111]3 years ago
8 0

Answer:

m=-5/8= 0.625   so the slope is 0.625

Step-by-step explanation:

just graph the points in a calculator or like on your phone or any device

uranmaximum [27]3 years ago
8 0

Answer:

Slope=-5/-8 OR 0.625

Step-by-step explanation:

y2-y1/x2-x1=3-8/-9-(-1)=-5/-8

OR

8-3/-1-(-9)=5/8=0.625

Both ways get the same decimal. I don't know which one you need to use.

Good luck and hope this helps.

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(Based on Q1 ~ Q3) According to the Bureau of the Census, 18.1% of the U.S. population lives in the Northeast, 21.9% inn the Mid
vekshin1

Answer:

We can therefore conclude that the geographical distribution of hotline callers could be the same as the U.S population distribution.

Step-by-step explanation:

The null Hypothesis: Geographical distribution of hotline callers could be the same as the U.S. population distribution

Alternative hypothesis: Geographical distribution of hotline callers could not be the same as the U.S. population distribution

The populations considered are the Midwest, South, Northeast, and west.

The number of categories, k = 4

Number of recent calls = 200

Let the number of estimated parameters that must be estimated, m = 0

The degree of freedom is given by the formula:

df = k - 1-m

df = 4 -1 - 0 = 3

Let the significance level be, α = 5% = 0.05

For  α = 0.05, and df = 3,

from the chi square distribution table, the critical value = 7.815

<u>Observed and expected frequencies of calls for each of the region:</u>

<u>Northeast</u>

Observed frequency = 39

It contains 18.1% of the US Population

The probability = 0.181

Expected frequency of call = 0.181 * 200 = 36.2

<u>Midwest</u>

Observed frequency = 55

It contains 21.9% of the US Population

The probability = 0.219

Expected frequency of call = 0.219 * 200 =43.8

<u>South</u>

Observed frequency = 60

It contains 36.7% of the US Population

The probability = 0.367

Expected frequency of call = 0.367 * 200 = 73.4

<u>West</u>

Observed frequency = 46

It contains 23.3% of the US Population

The probability = 0.233

Expected frequency of call = 0.233 * 200 = 46

x^{2} = \sum \frac{(O_{i} - E_{i})  ^{2} }{E_{i} } ,   i = 1, 2,.........k

Where O_{i} = observed frequency

E_{i} = Expected frequency

Calculate the test statistic value, x²

x^{2} = \frac{(39 - 36.2)^{2} }{36.2} + \frac{(55 - 43.8)^{2} }{43.8} + \frac{(60 - 73.4)^{2} }{73.4} + \frac{(46 - 46.6)^{2} }{46.6}

x^{2} = 5.535

Since the test statistic value, x²= 5.535 is less than the critical value = 7.815, the null hypothesis will not be rejected, i.e. it will be accepted. We can therefore conclude that the geographical distribution of hotline callers could be the same as the U.S population distribution.  

7 0
3 years ago
A customer deposits $500 in an account that pays 5% annual interest.
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Using the slope concept, it is found that:

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<h3>What is a slope?</h3>
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  • It's also the tangent of the angle of depression.

In this problem, the vertical change is the altitude of 10,000 feet.

The minimum horizontal distance is with an angle of 35º, hence:

\tan{35^{\circ}} = \frac{10000}{d}

d = \frac{10000}{\tan{35^{\circ}}}

d = 14281.5

The maximum horizontal distance is with an angle of 33º, hence:

\tan{33^{\circ}} = \frac{10000}{d}

d = \frac{10000}{\tan{33^{\circ}}}

d = 15398.6

You can learn more about the slope concept at brainly.com/question/22568180

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