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Vladimir79 [104]
3 years ago
7

5. The area of a rectangle is 120 square feet. What is the area of a rectangle that has

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
8 0
240 Bc 120 x 2 =240.
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What is the surface area of this figure?
disa [49]

Answer:

72 sq. mi

Step-by-step explanation:

Breaking this down, we have 2 right triangles with sides of 3, 4, and 5 miles, and 3 rectangles with dimensions 3 x 5, 4 x 5, and 5 x 5 miles. Remember that the area of a triangle is 1/2 x b x h , where b and h are the triangle's base and height. The base and height of the triangles at the bases of the figure are 3 and 4, so each triangle has an area of 1/2 x 3 x 4 = 1/2 x 12 = 6 sq. mi, or 6 + 6 = 12 sq. mi together.

Onto the rectangles, we can find their area by multiplying their length by their width. Since the width of these rectangles is the same for all three - 5 mi - we can make our lives a little easier and just "glue" the lengths together, giving us a longer rectangle with a length of 3 + 4 + 5 = 12 mi. Multiplying the two, we find the area of the rectangles to be 5 x 12 = 60 sq. mi.

Adding this area to the triangle's area gives us a total area of 12 + 60 = 72 sq. mi.

7 0
3 years ago
Read 2 more answers
Solve the exponential equation 1/2^x-5=8^x
dexar [7]

( \frac{1}{2} ) {}^{x - 5}  = 8 {}^{x}  \\  2 {}^{ - x + 5}  = 2 {}^{3x}  \\  - x + 5 = 3x \\  - 4x =  - 5 \\ x =  \frac{ - 5}{ - 4}  =  \frac{5}{4}
7 0
3 years ago
PLS HELP!
Marina CMI [18]

Answer:The domain for f(x) and g(x) is the set of all real numbers. Let f(x) = 2x2 + x − 3 and g(x) = x − 1. Find f(x) • g(x). The domain for f(​x) ...

1 answer

·

Top answer:

Just multiply the two functions. You can usea a variety of ways. I like t

Step-by-step explanation:

8 0
3 years ago
1. Which of the following could be an example of a function with a domain (-∞, ∞) and a range (-∞, 2)?
salantis [7]
That would be choice C  the limit  of f(x) is 2.
7 0
3 years ago
Can anybody help me on this?
Eduardwww [97]

Answer: second option.

Step-by-step explanation:

You need to descompose the radicand 8 and the radicand 50 into their prime factors:

8=2*2*2=2^2*2\\50=2*5*5=2*5^2

Then you can rewrite the expression:

\sqrt{8}+\sqrt{50}

=\sqrt{2^2*2}+\sqrt{2*5^2}

Since:

\sqrt{a^2}=a

You can simplify the expression:

=2\sqrt{2}+5\sqrt{2}

As the indices and the radicands are the same, you can make the addition:

=7\sqrt{2}

4 0
3 years ago
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