Answer:
not enough to figure out :/
Before the driver applies the brakes ( with the reaction time ):
d 1 = v0 · t = 20 m/s · 0.53 s = 10.6 m
After that:
v = v0 - a · t1
0 = 20 m/s - 7 · t1
7 · t1 = 20
t1 = 2.86 s
d 2 = v 0 · t1 - a · t1² / 2
d 2 = 20 m/s · 2.86 s - 7 m/s² · (2.86 s)²/2 = 57.2 m - 28.6 m = 28.6 m
d = d 1 + d 2 = 10.6 m + 28.6 m = 39.2 m
Answer: the stopping distance of a car is 39.2 m.
Answer:
60 cm
Step-by-step explanation:
2x the width and 2x the length gives you the perimeter. This can be represented by the equation:
2w + 2L = P
Use the information given in the word problem to fill in the variables.
2(59) + 2L = 238
118 + 2L = 238
move 118 to the other side of the equation.
2L = 238 - 118
2L = 120
move 2 to the other side of the equation.
L = 
L = 60
Answer:

8,3*0,25=2,10%(2d.p)
Step-by-step explanation:
Answer:
(fºg)(x) = x -2
Step-by-step explanation:
f(x) = x + 2
g(x) = x - 4
(fºg)(x) = ( x - 4) + 2
(fºg)(x) = x -2