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Savatey [412]
2 years ago
10

Question

Mathematics
1 answer:
Serhud [2]2 years ago
6 0

Answer:

The value of k is 11.

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

2=(k-3)/(5-1)

2=(k-3)/4

2*4=k-3

8=k-3

k=8+3

k=11

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Given x∥y and m∠3=124° .
makvit [3.9K]

Answer:

56

Step-by-step explanation:

I got this wrong but this is the answer

4 0
3 years ago
the lions won 16 games last year. this year the lions won 20 games. what is the percent increase in number of games the lions wo
jarptica [38.1K]
Last year won the lions 16 games last year and into this year the Lions won 20 games.

as the percentage increase is:

20/16

(20/4) / (16/4)

5/4
<span>
1.25 (125%)</span>
6 0
3 years ago
Which number can each term of the equation be multiplied by to eliminate the fractions before solving?
scoray [572]

Answer: 12

Step-by-step explanation:

You can multiply by 12 because to get rid of the fractions all terms should be divided by the LCM (ie the smallest multiple that is exactly divisible by 2, 4 and 3)

Multiples of 3 = 3, 6, 9, 12

Multiples of 4 = 4, 8, 12, 16

Multiples of 2 = 2, 4, 6, 8, 10, 12

Therefore the fractions should be multiplied by 12

5 0
2 years ago
Read 2 more answers
DO NOT SKIP!! Let’s see who’s smart enough to work out the problem if u get it correct I’ll mark u as BRAINLIEST SHOW THE WORK P
forsale [732]

Answer:

y=10.1(x)

x=\frac{y}{10.1}

Step-by-step explanation:

It is said in the problem that y would represent how much money she earns and x represents the number hours she works.

so it also said that the amount of Jessa earns is proportional to the amount of time she works .

finding y will be easy dividing 252.50 by 25 will give you 10.1

so how did we get that equation

y will represent the amount and x will represent the hours

4 0
3 years ago
The given two-parameter family is a solution of the indicated differential equation on the interval
mr_godi [17]

Answer:

I do 1 option for you as an example, you need to check the leftover by yourself.

Step-by-step explanation:

for d) y(0) = 0 and y'(pi) =0

y(0) = C_1e^0cos(0)+ C_2 e^0 sin(0) = 0 \longrightarrow C_1 = 0

y(x) ' = C_1e^x cos(x) - C_1e^x sin (x) + C_2e^x sin(x) + C_2e^x cos(x)

y(\pi)'=C_1e^\pi cos(\pi)- C_1e^\pi sin(\pi)+ C_2e^\pi sin(\pi) + C_2e^\pi cos (\pi)

Replace C_1 = 0 we have

y'(\pi) = -C_2e^\pi = 0

if and only if C_2 =0

Hence the given solution does not work.

then, d is NOT the correct answer.

3 0
3 years ago
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