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ruslelena [56]
2 years ago
11

What is the answer?????????? Please help!!!!!!

Mathematics
1 answer:
loris [4]2 years ago
7 0

Answer:

y = 1/2x + 1 is the awnser to the problem

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SSC's Tuatara is the fastest car in the world with 331 miles per hour
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5.517miles/min

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331/1h

=331/(1*60) because 1h=60min

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3 + 2x = y Given x = 4 y =
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Two buses leave towns 304 miles apart at the same time and travel toward each other. One bus travels 14 mih slower than the othe
8090 [49]

Answer:

The faster bus moves at 83mi/h and the slower one moves at 69mi/h.

Step-by-step explanation:

Let's define:

R₁ = rate of bus 1, this is the faster one.

R₂ = rate of bus 2, this is the slower one.

We know that one bus travels 14mi/h slower, then:

R₂ = R₁ - 14mi/h.

Now we know that:

Distance = Speed*Time.

If we add the distances that both busses travel in 2 hours, it should be equal to the initial distance between the buses, then:

R₁*2h + R₂*2h = 304 mi

Then we have the two equations:

R₂ = R₁ - 14mi/h

R₁*2h + R₂*2h = 304 mi

The first step is to replace the first equation in the second one, to get:

R₁*2h + (R₁ - 14mi/h)*2h = 304 mi

And now we can solve this for R₁.

R₁*2h + R₁*2h - 14mi/h*2h = 304 mi

R₁*4h - 28mi = 304mi

R₁*4h = 304mi + 28mi = 332mi

R₁ = 332mi/4h = 83mi/h

The faster bus moves at 83mi/h

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R₂ = R₁ - 14mi/h = 83mi/h - 14mi/h = 69 mi/h

7 0
2 years ago
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