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Lady bird [3.3K]
2 years ago
8

The gradient of the line segment between the points (2,-3) and (4,-7).

Mathematics
2 answers:
timurjin [86]2 years ago
4 0

Answer:

gradient = - 2

Step-by-step explanation:

Calculate the gradient (slope ) m using the gradient formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (2, - 3 ) and (x₂, y₂ ) = (4, - 7 )

m = \frac{-7-(-3)}{4-2} = \frac{-7+3}{2} = \frac{-4}{2} = - 2

skad [1K]2 years ago
3 0

To find the gradient of a line you use this equation: Rise / Run

I am assuming this is a graph where both the x and y-axis increase in value by one.

So first of all, you should draw out this graph.

Second, draw a point at each of the given coordinates.

Now, join these points by drawing a right angle triangle. Put simply, draw a line from the point (4, -7) down until it is on the same level as the point (2, -3), then draw a line across.

Finally, measure the length of both these sides and use them in the equation above.

Let's assume the rise (vertical line) and the run (horizontal line) are 5 and 8 respectively. We can do 5/8 to get a gradient which is 0.625.

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I need help on this question, someone please help!!
Tju [1.3M]

Answer:

y=−x−1/3x−8

Step-by-step explanation:

y=8x−1/3x+1

To find the inverse function, swap x and y, and solve the resulting equation for x.

If the initial function is not one-to-one, then there will be more than one inverse.

So, swap the variables: y=8x−1/3x+1 becomes x=8y−1/3y+1.

Now, solve the equation x=8y−1/3y+1 for y.

y=−x−1/3x−8

Sorry I was in a rush and couldn't do the fractions as formulae. Hope it helped anyways.

7 0
2 years ago
Step by set
Roman55 [17]

Answer:

2 2/3 or 8/3

Step-by-step explanation:

Step by step I am guessing? (Is that what each question is for?)

STEP 1

First we have to find 1/3 of 23:

23/3= 1/3 of 23

Then:

5/1 = 15/3

STEP 2

Subtract:

23-15= 8/3

8/3 or 2 2/3

3 0
2 years ago
Express the statement "A rectangular field with an area of 120m' has it length 12mn longer than the width" as quadratic equation
navik [9.2K]

Answer:

The quadratic equation is x^2 -12x -120 = 0

where x represents the length of the field

Step-by-step explanation:

We want to make an expression in terms of a quadratic equation;

Let the length of the field be x mm , then the width will be (x-12) mm

Mathematically , the area of the field will be L * B

Thus;

x * (x-12) = 120

That gives;

x^2 -12x = 120

x^2 -12x -120 = 0

6 0
2 years ago
Leo bought 6 chew toys for his new puppy each chew toy cost $4 how much did Leo spend for the chew toys
Nikolay [14]
6*4 equals 24 bam easy mat
8 0
3 years ago
Read 2 more answers
How many different 4 digit even numbers can be written using 0,5,6,3,8,7?<br><br> help asap please!!
fiasKO [112]

Step-by-step explanation:

I guess that means the digits can not be repeated in such a number.

let's start with how many numbers in general can be created :

we have 6 basic digits, and we are pulling 4 of them for a number.

if the sequence of the pulled digits would not matter, it would be combinations C (6, 4).

but we are creating different numbers, so the sequence of the digits does matter. so, it is permutations P (6, 4).

P(6, 4) = 6!/(6-4)! = 6!/2! = 6×5×4×3 = 360

so. bauxite, we can create 360 different 4 digit numbers out of these 6 digits.

but not all of them are wanted.

for example, I assume we don't want the numbers that start with a 0, because they would normally count as 3-digit numbers.

if that assumption is correct, we need to find how many would start with a 0, and subtract those from the total number.

since we are handling all 6 digits in the same way, an equal number must start with 0, with 5, with 6, with 3, with 8 and with 7.

so, 1/6 of the total number start with 0 : 360×1/6 = 60.

that means the total number of 4-digit numbers out of these 6 digits that do not start with 0 is 360-60 = 300.

but we are still not finished : we only want even numbers. that means they end with 0, 6 or 8.

in the same way we considered the first position, we consider also the last position. we have an equal amount of numbers that end with the different digits.

and so, we have 1/6 of 300 for each ending digit.

we want the specified 3 digits as end digits, so we get

3×1/6 of the 300 = 1/2 × 300 = 150

so, we can write 150 different 4-digit even numbers out of these 6 digits.

3 0
2 years ago
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