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Lemur [1.5K]
3 years ago
8

Divide ( 4x^2 +12x+4)/(x+2) Use long polynomial division.

Mathematics
1 answer:
NemiM [27]3 years ago
3 0
I think this is the answer you are looking for. I hope this helps.

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Fifty less than four times a number is ten. What is this number?
Mashcka [7]

Let the number be x.

The equation is:

4x - 50 = 10

=> 4x = 10 + 50

=> 4x = 60

=> x = 60/4

=> x = 15

So, the number is 15.

8 0
3 years ago
Caleb and Sergio stacked boxes on a shelf. Caleb lifted 14 boxes and Sergio lifted 12 boxes. The boxes that Sergio lifted each w
Allushta [10]

Answer:

C

Step-by-step explanation:

The answer is c. It adds to the weight of each box by 10 and multiplies by 12 to represent the 12 boxes.

5 0
3 years ago
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Find the equation of a line that is parallel to y = 5x + 7 and passes through (4, 3)
vredina [299]

Answer:

B) y=5x-17

Step-by-step explanation:

I got this answer, by first making sure it was parallel to y=5x+7. Which was easy because the only thing they need to be parallel is the same slope, in this case was 5. Next I pluged in (4,3) to y=5x-17. I substituted 4 into x and got 20. Then I substituted 3 into y. Since 20-17 is equal to 3, then B. is your answer.

7 0
4 years ago
Read 2 more answers
An airplane is flying at a speed of 580 km/h on a bearing of North 60° east. The wind blows from a bearing of North 45° west at
kiruha [24]

Answer:

t

Step-by-step explanation:

yhhhhh6bbbb h 66yltktktktoitt

5 0
3 years ago
Tensile strength tests were performed on two different grades of aluminum spars used in manufacturing the wing of a commercial t
jekas [21]

Answer:

(12.1409, 14.0591

Step-by-step explanation:

Given that Tensile strength tests were performed on two different grades of aluminum spars used in manufacturing the wing of a commercial transport aircraft. From past experience with the spar manufacturing process and the testing procedure, the standard deviations of tensile strengths are assumed to be known.

Group   Group One     Group Two  

Mean 87.600 74.500

SD 1.000 1.500

SEM 0.316 0.433

N 10      12    

The mean of Group One minus Group Two equals 13.100

standard error of difference = 0.556

 90% confidence interval of this difference:  

(13.1-1.725*0.556,13.1+1.725*0.556)\\=(12.1409, 14.0591)

  t = 23.5520

 df = 20

4 0
3 years ago
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